java - 从流中获取最后 n 个元素

Question

我想知道有没有替代方法

List<X> lastN = all.subList(Math.max(0, all.size() - n), all.size());

与 stream用法？

Answer 1

使用 Stream.skip()

Returns a stream consisting of the remaining elements of this stream after discarding the first n elements of the stream. If this stream contains fewer than n elements then an empty stream will be returned.

all.stream().skip(Math.max(0, all.size() - n)).forEach(doSomething);