python - 如何从子类调用基类的 __init__ 方法？

Question

这个问题在这里已经有了答案:

How to invoke the super constructor in Python? (7 个回答)

关闭 6年前。

如果我有一个 python 类:

class BaseClass(object):
#code and the init function of the base class

然后我定义一个子类如:

class ChildClass(BaseClass):
#here I want to call the init function of the base class

如果基类的 init 函数接受一些我将它们作为子类的 init 函数的参数的参数，我如何将这些参数传递给基类？

我写的代码是:

class Car(object):
    condition = "new"

    def __init__(self, model, color, mpg):
        self.model = model
        self.color = color
        self.mpg   = mpg

class ElectricCar(Car):
    def __init__(self, battery_type, model, color, mpg):
        self.battery_type=battery_type
        super(ElectricCar, self).__init__(model, color, mpg)

我哪里错了？

Answer 1

你可以使用 super(ChildClass, self).__init__()

class BaseClass(object):
    def __init__(self, *args, **kwargs):
        pass

class ChildClass(BaseClass):
    def __init__(self, *args, **kwargs):
        super(ChildClass, self).__init__(*args, **kwargs)

你的缩进不正确，修改后的代码如下:

class Car(object):
    condition = "new"

    def __init__(self, model, color, mpg):
        self.model = model
        self.color = color
        self.mpg   = mpg

class ElectricCar(Car):
    def __init__(self, battery_type, model, color, mpg):
        self.battery_type=battery_type
        super(ElectricCar, self).__init__(model, color, mpg)

car = ElectricCar('battery', 'ford', 'golden', 10)
print car.__dict__

这是输出:

{'color': 'golden', 'mpg': 10, 'model': 'ford', 'battery_type': 'battery'}