java - HttpURLConnection 发送 POST 请求，即使 httpCon.setRequestMethod ("GET");已设置

Question

这是我的代码:

String addr = "http://172.26.41.18:8080/domain/list";

URL url = new URL(addr);
HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
httpCon.setDoOutput(true);
httpCon.setDoInput(true);
httpCon.setUseCaches(false);
httpCon.setAllowUserInteraction(false);
httpCon.setRequestMethod("GET");
httpCon.addRequestProperty("Authorization", "Basic YWRtaW4fYFgjkl5463");

httpCon.connect();

OutputStreamWriter out = new OutputStreamWriter(httpCon.getOutputStream());

System.out.println(httpCon.getResponseCode());
System.out.println(httpCon.getResponseMessage());

out.close();

我看到的回应:

500 Server error

我打开我的 httpCon 变量，然后我看到了:

POST /rest/platform/domain/list HTTP/1.1

为什么我用 httpCon.setRequestMethod("GET"); 设置为 GET 却设置为 POST？

Answer 1

httpCon.setDoOutput(true); 将请求方法隐式设置为 POST，因为这是您想要发送请求正文时的默认方法。

如果您想使用 GET，请删除该行并删除 OutputStreamWriter out = new OutputStreamWriter(httpCon.getOutputStream()); 行。您不需要为 GET 请求发送请求正文。

对于一个简单的 GET 请求应该执行以下操作:

String addr = "http://172.26.41.18:8080/domain/list";
URL url = new URL(addr);
HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
httpCon.setUseCaches(false);
httpCon.setAllowUserInteraction(false);
httpCon.addRequestProperty("Authorization", "Basic YWRtaW4fYFgjkl5463");
System.out.println(httpCon.getResponseCode());
System.out.println(httpCon.getResponseMessage());

另见:

• Using java.net.URLConnection to fire and handle HTTP requests

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Unrelated 到具体问题，您的 Authorization header 值的密码部分似乎没有正确进行 Base64 编码。也许它被打乱了，因为它是示例性的，但即使不是，我也会修复你的 Base64 编码方法。