java - org.hibernate.QueryException : could not resolve property: filename

Question

我正在使用 Hibernate Criteria 从我的表 contaque_recording_log 中的列 filename 中获取值。

但是当我得到结果时，它会抛出一个异常

org.hibernate.QueryException: could not resolve property: filename of: com.contaque.hibernateTableMappings.contaque_recording_log

我的table bean是:

import java.util.Date;
import javax.persistence.*;


@Entity
@Table(name="contaque_recording_log")
public class contaque_recording_log implements java.io.Serializable{
    private static final long serialVersionUID = 1111222233334404L;
    @Id
    @Column(name="logId", insertable=true, updatable=true, unique=false)
    private Integer logId;

    @Column(name="userName", insertable=true, updatable=true, unique=false)
    private String userName;

    @Column(name="ext", insertable=true, updatable=true, unique=false)
    private String ext;

    @Column(name="phoneNumber", insertable=true, updatable=true, unique=false)
    private String phoneNumber;

    @Column(name="callerId", insertable=true, updatable=true, unique=false)
    private String callerId;

    @Column(name="fileName", insertable=true, updatable=true, unique=false)
    private String fileName;


    @Column(name="campName", insertable=true, updatable=true, unique=false)
    private String campName;

    @Temporal(javax.persistence.TemporalType.TIMESTAMP)
    @Column(name="eventDate", insertable=true, updatable=true, unique=false)
    private Date eventDate;

    @Column(name="disposition", insertable=true, updatable=true, unique=false)
    private String disposition;

    @Column(name="duration", insertable=true, updatable=true, unique=false)
    private String duration;

    @Column(name="calltype", insertable=true, updatable=true, unique=false)
    private String calltype;

    public Date getEventDate() {
        return eventDate;
    }

    public void setEventDate(Date eventDate) {
        this.eventDate = eventDate;
    }

    public String getCallerId() {
        return callerId;
    }

    public void setCallerId(String callerId) {
        this.callerId = callerId;
    }

    public String getExt() {
        return ext;
    }

    public void setExt(String ext) {
        this.ext = ext;
    }

    public String getFileName() {
        return fileName;
    }

    public void setFileName(String fileName) {
        this.fileName = fileName;
    }

    public String getPhoneNumber() {
        return phoneNumber;
    }

    public void setPhoneNumber(String phoneNumber) {
        this.phoneNumber = phoneNumber;
    }

    public String getUserName() {
        return userName;
    }

    public void setUserName(String userName) {
        this.userName = userName;
    }

    public Integer getLogId() {
        return logId;
    }

    public void setLogId(Integer logId) {
        this.logId = logId;
    }

    public String getCampName() {
        return campName;
    }

    public void setCampName(String campName) {
        this.campName = campName;
    }

    public String getDisposition() {
        return disposition;
    }

    public void setDisposition(String disposition) {
        this.disposition = disposition;
    }

    public String getDuration() {
        return duration;
    }

    public void setDuration(String duration) {
        this.duration = duration;
    }

    public String getCalltype() {
        return calltype;
    }

    public void setCalltype(String calltype) {
        this.calltype = calltype;
    }
}

我的 hibernateUtil 类从我得到 hibernate session 的地方:

public enum HibernateUtilSpice {
    INSTANCE;
    public static SessionFactory sessionFactory = null;

    private synchronized SessionFactory getSessionFactory(){

        if(sessionFactory == null){
            Configuration config = new Configuration();
            config.addAnnotatedClass(contaque_recording_log.class);
            config.addAnnotatedClass(contaque_servers.class);
            config.configure();

            //get the properties from Hibernate configuration file
            Properties configProperties = config.getProperties();
            ServiceRegistryBuilder serviceRegisteryBuilder = new ServiceRegistryBuilder();
            ServiceRegistry serviceRegistry = serviceRegisteryBuilder.applySettings(configProperties).buildServiceRegistry();
            sessionFactory = config.buildSessionFactory(serviceRegistry);
        }
        return sessionFactory;
    }

    public Session getSession(){
        return getSessionFactory().openSession();
    }
}

我从表中获取数据的方法:

public String getFileName() {

    try{
        hibernateSession = HibernateUtilSpice.INSTANCE.getSession();
        Criteria criteria = hibernateSession.createCriteria(contaque_recording_log.class);
        criteria.add(Restrictions.eq("campname", "spice"));
        criteria.add(Restrictions.eq("disposition", "WN"));
        criteria.setProjection(Projections.property("filename"));
        List list = criteria.list();
        for (Object object : list) {
            System.out.println("List obj: " + object);
        }
    } catch (Exception e){
        e.printStackTrace();
    } finally {
        hibernateSession.flush();
        hibernateSession.close();
    }
    return filename;
}

如果我打印 criteria.toString()，则 O/P 为:

CriteriaImpl(com.contaque.hibernateTableMappings.contaque_recording_log:this[][campname=spice, disposition=WN]filename)

我哪里出错了，如何从我的表中获取数据？

Answer 1

Hibernate 查询对属性名称区分大小写(因为它们最终依赖于 @Entity 上的 getter/setter 方法)。

确保在条件查询中将该属性称为 fileName，而不是 filename。

具体来说，Hibernate 在执行 Criteria 查询时会调用 filename 属性的 getter 方法，因此它会寻找一个名为 getFilename() 的方法。但是该属性称为 FileName 和 getter getFileName()。

所以，像这样改变投影:

criteria.setProjection(Projections.property("fileName"));