python - 从列表中删除与子字符串匹配的项目

Question

如果一个元素与子字符串匹配，如何从列表中删除它？

我尝试使用 pop() 和 enumerate 方法从列表中删除一个元素，但似乎我缺少一些需要删除的连续项目:

sents = ['@$\tthis sentences needs to be removed', 'this doesnt',
     '@$\tthis sentences also needs to be removed',
     '@$\tthis sentences must be removed', 'this shouldnt',
     '# this needs to be removed', 'this isnt',
     '# this must', 'this musnt']

for i, j in enumerate(sents):
  if j[0:3] == "@$\t":
    sents.pop(i)
    continue
  if j[0] == "#":
    sents.pop(i)

for i in sents:
  print i

输出:

this doesnt
@$  this sentences must be removed
this shouldnt
this isnt
#this should
this musnt

期望的输出:

this doesnt
this shouldnt
this isnt
this musnt

Answer 1

像这样简单的东西怎么样:

>>> [x for x in sents if not x.startswith('@$\t') and not x.startswith('#')]
['this doesnt', 'this shouldnt', 'this isnt', 'this musnt']