java - 如何将单词转换为数字？

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我想将包含字母字符的单词转换为 Java 中的代表数字。

例如，404 应计算为数字 404。

如果字母像 asdf 那样乱码，那就是错误。

我知道我可以 convert bare Characters to their ascii equivalent Integer ，将它们附加在一起，但我只想提取英文单词短语后面的数字。

Answer 1

这是我在尝试解决相同问题时想出的一些代码。请记住，我不是专业人士，也没有疯狂的经验。它并不慢，但我相信它可以更快/更清洁/等。我用它来将语音识别的单词转换为数字，以便在我自己的“Jarvis”a la Iron Man 中进行计算。它可以处理 10 亿以下的数字，尽管它可以很容易地扩展到包含更高数量级的数据，而只需花费很少的时间。

public static final String[] DIGITS = {"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
public static final String[] TENS = {null, "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"};
public static final String[] TEENS = {"ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
public static final String[] MAGNITUDES = {"hundred", "thousand", "million", "point"};
public static final String[] ZERO = {"zero", "oh"};

public static String replaceNumbers (String input) {
    String result = "";
    String[] decimal = input.split(MAGNITUDES[3]);
    String[] millions = decimal[0].split(MAGNITUDES[2]);

    for (int i = 0; i < millions.length; i++) {
        String[] thousands = millions[i].split(MAGNITUDES[1]);

        for (int j = 0; j < thousands.length; j++) {
            int[] triplet = {0, 0, 0};
            StringTokenizer set = new StringTokenizer(thousands[j]);

            if (set.countTokens() == 1) { //If there is only one token given in triplet
                String uno = set.nextToken();
                triplet[0] = 0;
                for (int k = 0; k < DIGITS.length; k++) {
                    if (uno.equals(DIGITS[k])) {
                        triplet[1] = 0;
                        triplet[2] = k + 1;
                    }
                    if (uno.equals(TENS[k])) {
                        triplet[1] = k + 1;
                        triplet[2] = 0;
                    }
                }
            }


            else if (set.countTokens() == 2) {  //If there are two tokens given in triplet
                String uno = set.nextToken();
                String dos = set.nextToken();
                if (dos.equals(MAGNITUDES[0])) {  //If one of the two tokens is "hundred"
                    for (int k = 0; k < DIGITS.length; k++) {
                        if (uno.equals(DIGITS[k])) {
                            triplet[0] = k + 1;
                            triplet[1] = 0;
                            triplet[2] = 0;
                        }
                    }
                }
                else {
                    triplet[0] = 0;
                    for (int k = 0; k < DIGITS.length; k++) {
                        if (uno.equals(TENS[k])) {
                            triplet[1] = k + 1;
                        }
                        if (dos.equals(DIGITS[k])) {
                            triplet[2] = k + 1;
                        }
                    }
                }
            }

            else if (set.countTokens() == 3) {  //If there are three tokens given in triplet
                String uno = set.nextToken();
                String dos = set.nextToken();
                String tres = set.nextToken();
                for (int k = 0; k < DIGITS.length; k++) {
                    if (uno.equals(DIGITS[k])) {
                        triplet[0] = k + 1;
                    }
                    if (tres.equals(DIGITS[k])) {
                        triplet[1] = 0;
                        triplet[2] = k + 1;
                    }
                    if (tres.equals(TENS[k])) {
                        triplet[1] = k + 1;
                        triplet[2] = 0;
                    }
                }
            }

            else if (set.countTokens() == 4) {  //If there are four tokens given in triplet
                String uno = set.nextToken();
                String dos = set.nextToken();
                String tres = set.nextToken();
                String cuatro = set.nextToken();
                for (int k = 0; k < DIGITS.length; k++) {
                    if (uno.equals(DIGITS[k])) {
                        triplet[0] = k + 1;
                    }
                    if (cuatro.equals(DIGITS[k])) {
                        triplet[2] = k + 1;
                    }
                    if (tres.equals(TENS[k])) {
                        triplet[1] = k + 1;
                    }
                }
            }
            else {
                triplet[0] = 0;
                triplet[1] = 0;
                triplet[2] = 0;
            }

            result = result + Integer.toString(triplet[0]) + Integer.toString(triplet[1]) + Integer.toString(triplet[2]);
        }
    }

    if (decimal.length > 1) {  //The number is a decimal
        StringTokenizer decimalDigits = new StringTokenizer(decimal[1]);
        result = result + ".";
        System.out.println(decimalDigits.countTokens() + " decimal digits");
        while (decimalDigits.hasMoreTokens()) {
            String w = decimalDigits.nextToken();
            System.out.println(w);

            if (w.equals(ZERO[0]) || w.equals(ZERO[1])) {
                result = result + "0";
            }
            for (int j = 0; j < DIGITS.length; j++) {
                if (w.equals(DIGITS[j])) {
                    result = result + Integer.toString(j + 1);
                }   
            }

        }
    }

    return result;
}

输入必须是语法正确的语法，否则会出现问题(创建一个函数来删除“and”)。一个字符串输入“二亿二百万五万三千点零八五八哦二”返回:

two hundred two million fifty three thousand point zero eight five eight oh two
202053000.085802
It took 2 milliseconds.