python - 如何在 Python 中对函数进行深度复制？

Question

我想在 Python 中制作一个函数的深拷贝。根据 documentation，copy 模块没有帮助。 ，上面写着:

This module does not copy types like module, method, stack trace, stack frame, file, socket, window, array, or any similar types. It does “copy” functions and classes (shallow and deeply), by returning the original object unchanged; this is compatible with the way these are treated by the pickle module.

我的目标是拥有两个具有相同实现但具有不同文档字符串的函数。

def A():
    """A"""
    pass

B = make_a_deepcopy_of(A)
B.__doc__ = """B"""

那么如何做到这一点呢？

Answer 1

FunctionType 构造函数用于制作函数的深拷贝。

import types
def copy_func(f, name=None):
    return types.FunctionType(f.func_code, f.func_globals, name or f.func_name,
        f.func_defaults, f.func_closure)

def A():
    """A"""
    pass
B = copy_func(A, "B")
B.__doc__ = """B"""