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java - 如何使用或注释不应保留在数据库中的 JPA 实体 bean 中的虚拟字段

转载 作者:IT老高 更新时间:2023-10-28 20:37:03 34 4
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我有此代码用于使用 Struts2 操作类进行登录验证,该操作类调用 EJB 进行 LDAP 验证,然后如果(LDAP 凭据)验证,则使用 JPA 实体 bean 查询用户数据库以获取其余用户信息就像一个 POJO。与用户名、用户 ID 和其他用户信息不同,密码不存储在数据库中,但为了 POJO getter 和 setter 方法,我尝试包含一个虚拟密码字段 - 用于为 Struts2 操作表单提供服务。

问题是在 ldap 身份验证之后,出现一个异常,指出数据库中不存在“密码”列(这本来就不应该存在!)

Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.0.1.v20100213-r6600): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'PASSWORD' in 'field list'
Error Code: 1054
Call: SELECT PERSON_ID, ACTIVE_USER, EMAIL, FIRSTNAME, SURNAME, PASSWORD, FULLNAME, EMPLOYEE_NUMBER FROM xxte_employees WHERE (ACTIVE_USER = ?)
bind => [john.doe]
Query: ReadAllQuery(name="XxteEmployees.validateLogin" referenceClass=XxteEmployees sql="SELECT PERSON_ID, ACTIVE_USER, EMAIL, FIRSTNAME, SURNAME, PASSWORD, FULLNAME, EMPLOYEE_NUMBER FROM xxte_employees WHERE (ACTIVE_USER = ?)")
at org.eclipse.persistence.exceptions.DatabaseException.sqlException(DatabaseException.java:333)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.basicExecuteCall(DatabaseAccessor.java:687)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeCall(DatabaseAccessor.java:530)
at org.eclipse.persistence.sessions.server.ServerSession.executeCall(ServerSession.java:529)
....

这是来自实体 bean 的代码:

public class XxteEmployees implements Serializable {
private static final long serialVersionUID = 1L;
@Column(name = "ACTIVE_USER")
private String activeUser;
@Column(name = "EMAIL")
private String email;
@Id
@Basic(optional = false)
@Column(name = "PERSON_ID")
private Double personId;
@Column(name = "EMPLOYEE_NUMBER")
private Double employeeNumber;
@Column(name = "FIRSTNAME")
private String firstname;
@Column(name = "SURNAME")
private String surname;

private String fullname;

private String password;

public XxteEmployees() {
}

public XxteEmployees(Double personId) {
this.personId = personId;
}

public String getActiveUser() {
return activeUser;
}

public void setActiveUser(String activeUser) {
this.activeUser = activeUser;
}

public String getEmail() {
return email;
}

public void setEmail(String email) {
this.email = email;
}

public Double getPersonId() {
return personId;
}

public void setPersonId(Double personId) {
this.personId = personId;
}

public Double getEmployeeNumber() {
return employeeNumber;
}

public void setEmployeeNumber(Double employeeNumber) {
this.employeeNumber = employeeNumber;
}

public String getFirstname() {
return firstname;
}

public void setFirstname(String firstname) {
this.firstname = firstname;
}


public String getSurname() {
return surname;
}

public void setSurname(String surname) {
this.surname = surname;
}

// BEGIN: objects not in db

public String getFullname() {
return firstname + ' ' + surname;
}


public void setFullname(String fullname) {
this.fullname = firstname + ' ' + surname;;
}

public String getPassword() {
return sifre;
}

public void setPassword(String password) {
this.password = password;
}
// END: objects not in db

有什么解决方法吗?

最佳答案

注释您不希望保留为 @Transient 的任何字段。它在 javax.persistence 包中。

关于java - 如何使用或注释不应保留在数据库中的 JPA 实体 bean 中的虚拟字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4115861/

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