python - 如何在 python 中对 datetime.timedelta 执行除法？

Question

我希望能够做到以下几点:

num_intervals = (cur_date - previous_date) / interval_length

或

print (datetime.now() - (datetime.now() - timedelta(days=5))) 
      / timedelta(hours=12)
# won't run, would like it to print '10'

但时间增量不支持除法运算。有没有办法可以为 timedeltas 实现除法？

编辑: 看起来这是在 Python 3.2 中添加的(感谢 rincewind!):http://bugs.python.org/issue2706

Answer 1

整数除法和乘法似乎有效out of the box :

>>> from datetime import timedelta
>>> timedelta(hours=6)
datetime.timedelta(0, 21600)
>>> timedelta(hours=6) / 2
datetime.timedelta(0, 10800)