java 。比较字符串时忽略重音符号

Question

问题很简单。 JAVA中是否有任何函数可以比较两个字符串并忽略重音字符返回true？

即

String x = "Joao";
String y = "João";

返回相等的。

谢谢

Answer 1

我认为您应该使用 Collator类(class)。它允许您设置强度和语言环境，它会适本地比较字符。

来自 Java 1.6 API:

You can set a Collator's strength property to determine the level of difference considered significant in comparisons. Four strengths are provided: PRIMARY, SECONDARY, TERTIARY, and IDENTICAL. The exact assignment of strengths to language features is locale dependant. For example, in Czech, "e" and "f" are considered primary differences, while "e" and "ě" are secondary differences, "e" and "E" are tertiary differences and "e" and "e" are identical.

我认为这里的重点(人们试图提出的)是“Joao”和“João”永远不应该被认为是平等的，但是如果你正在做排序你不希望他们根据他们的 ASCII 值，因为那样你会得到像 Joao、John、João 这样的东西，这不好。使用 collat​​or 类肯定可以正确处理这个问题。