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c++ - 未定义模板的隐式实例化 'std::basic_string, std::allocator>'

转载 作者:IT老高 更新时间:2023-10-28 13:58:59 25 4
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在我一直在做的项目中,我们必须将 Cocoa 通知从 C++ 子项目发送到它上面的主项目。为此,我们构建了一个映射来充当通知的 userInfo 字典的键值存储。

在其中一个项目中,以下代码编译得很好:

std::map<std::string, std::string> *userInfo = new std::map<std::string, std::string>;
char buffer[255];

sprintf(buffer, "%i", intValue1);
userInfo->insert(std::pair<std::string, std::string>("intValue1", std::string(buffer)));

sprintf(buffer, "%i", intValue2);
userInfo->insert(std::pair<std::string, std::string>("intValue2", std::string(buffer)));

if(condition)
userInfo->insert(std::pair<std::string, std::string>("conditionalValue", "true"));

PostCocoaNotification("notificationName", *userInfo);

但是,当它被复制到另一个子项目中的相同文件中时,编译器会在 userInfo->insert 调用中抛出以下内容:

"Implicit instantiation of undefined template 'std::basic_string<char, std::char_traits<char>, std::allocator<char> >'" 

..它找不到 PostCocoaNotification 的函数:

No matching function for call to 'PostCocoaNotification'

此外,它会在系统 header 中引发以下错误:

/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk/usr/include/c++/4.2.1/bits/stl_pair.h:73:11: Implicit instantiation of undefined template 'std::basic_string<char, std::char_traits<char>, std::allocator<char> >'
/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk/usr/include/c++/4.2.1/bits/stl_pair.h:74:11: Implicit instantiation of undefined template 'std::basic_string<char, std::char_traits<char>, std::allocator<char> >'
/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk/usr/include/c++/4.2.1/bits/stl_pair.h:73:11: Implicit instantiation of undefined template 'std::basic_string<char, std::char_traits<char>, std::allocator<char> >'
/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk/usr/include/c++/4.2.1/bits/stl_tree.h:1324:13: Cannot initialize a parameter of type '_Link_type' (aka '_Rb_tree_node<std::pair<const std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::basic_string<char, std::char_traits<char>, std::allocator<char> > > > *') with an rvalue of type '_Const_Link_type' (aka 'const _Rb_tree_node<std::pair<const std::basic_string<char, std::char_traits<char>, std::allocator<char> >, std::basic_string<char, std::char_traits<char>, std::allocator<char> > > > *')

我不知道我做了什么导致这种困惑,尤其是当代码在另一个子项目中运行良好时(成功发送通知)。任何对此问题的见解都将受到欢迎。

最佳答案

您需要包含此 header :

#include <string>

关于c++ - 未定义模板的隐式实例化 'std::basic_string<char, std::char_traits<char>, std::allocator<char>>',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19223360/

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