spring - 如何使用spring来编码和解码xml？

Question

我有一个 Spring Boot 项目。我的项目中有一些 xsd。我已经使用 maven-jaxb2-plugin 生成了这些类。我用过this让示例 Spring Boot 应用程序运行的教程。

import org.kaushik.xsds.XOBJECT;

@SpringBootApplication
public class JaxbExample2Application {

public static void main(String[] args) {
    //SpringApplication.run(JaxbExample2Application.class, args);
    XOBJECT xObject = new XOBJECT('a',1,2);

    try {
        JAXBContext jc = JAXBContext.newInstance(User.class);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(xObject, System.out);

    } catch (PropertyException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (JAXBException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
 }
}

但我担心的是我需要映射架构的所有 jaxb 类。 Spring 中还有什么东西可以用来让我的任务更轻松。我看过 Spring OXM项目，但它在 xml 中配置了应用程序上下文。 Spring Boot 有什么我可以开箱即用的东西吗？任何示例都会有所帮助。

编辑

我试过 xerx593's answer我使用 main 方法进行了一个简单的测试

    JaxbHelper jaxbHelper = new JaxbHelper();
    Jaxb2Marshaller marshaller = new Jaxb2Marshaller();
    marshaller.setClassesToBeBound(XOBJECT.class);
    jaxbHelper.setMarshaller(marshaller);
    XOBJECT xOBJECT= (PurchaseOrder)jaxbHelper.load(new StreamSource(new FileInputStream("src/main/resources/PurchaseOrder.xml")));
    System.out.println(xOBJECT.getShipTo().getName());

它运行得非常好。现在我只需要使用 Spring Boot 将其插入即可。

Answer 1

OXM 绝对适合您!

Jaxb2Marshaller 的简单 java 配置如下所示:

//...
import java.util.HashMap;
import org.springframework.oxm.jaxb.Jaxb2Marshaller;
//...

@Configuration
public class MyConfigClass {
    @Bean
    public Jaxb2Marshaller jaxb2Marshaller() {
        Jaxb2Marshaller marshaller = new Jaxb2Marshaller();
        marshaller.setClassesToBeBound(new Class[]{
           //all the classes the context needs to know about
           org.kaushik.xsds.All.class,
           org.kaushik.xsds.Of.class,
           org.kaushik.xsds.Your.class,
           org.kaushik.xsds.Classes.class
        });
        // "alternative/additiona - ly":
          // marshaller.setContextPath(<jaxb.context-file>)
          // marshaller.setPackagesToScan({"com.foo", "com.baz", "com.bar"});

        marshaller.setMarshallerProperties(new HashMap<String, Object>() {{
          put(javax.xml.bind.Marshaller.JAXB_FORMATTED_OUTPUT, true);
          // set more properties here...
        }});

        return marshaller;
    }
}

在您的应用程序/服务类中，您可以这样处理:

import java.io.InputStream;
import java.io.StringWriter;
import javax.xml.bind.JAXBException;
import javax.xml.transform.Result;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import org.springframework.oxm.jaxb.Jaxb2Marshaller;  

@Component
public class MyMarshallerWrapper {
   // you would rather:
   @Autowired
   private Jaxb2Marshaller  marshaller;
   // than:
   // JAXBContext jc = JAXBContext.newInstance(User.class);
   // Marshaller marshaller = jc.createMarshaller();

   // marshalls one object (of your bound classes) into a String.
   public <T> String marshallXml(final T obj) throws JAXBException {
      StringWriter sw = new StringWriter();
      Result result = new StreamResult(sw);
      marshaller.marshal(obj, result);
      return sw.toString();
   }

   // (tries to) unmarshall(s) an InputStream to the desired object.
   @SuppressWarnings("unchecked")
   public <T> T unmarshallXml(final InputStream xml) throws JAXBException {
      return (T) marshaller.unmarshal(new StreamSource(xml));
   }
}

见 Jaxb2Marshaller-javadoc ，以及相关的 Answer