java - 在spring boot websocket中向特定用户发送通知

Question

我想向特定客户发送通知。

例如用户名用户

@Configuration
@EnableWebSocketMessageBroker
public class WebSocketConfiguration extends
    AbstractWebSocketMessageBrokerConfigurer {

        @Override
        public void registerStompEndpoints(StompEndpointRegistry stompEndpointRegistry) {
            stompEndpointRegistry.addEndpoint("/socket")
                    .setAllowedOrigins("*")
                    .withSockJS();
        }

        @Override
        public void configureMessageBroker(MessageBrokerRegistry registry) {
            registry.enableSimpleBroker("/topic", "/queue");
            registry.setApplicationDestinationPrefixes("/app");

        }

Controller

@GetMapping("/notify")
public String getNotification(Principal principal) {
    String username = "user";

    notifications.increment();
    logger.info("counter" + notifications.getCount() + "" + principal.getName());
    //  logger.info("usersend:"+sha.getUser().getName()) ; //user

    template.convertAndSendToUser(principal.getName(), "queue/notification", notifications);

    return "Notifications successfully sent to Angular !";
}

客户端

角度服务

connect() {
    let socket = new SockJs(`api/socket`);

    let stompClient = Stomp.over(socket);

    return stompClient;
}

角度组件

 let stompClient = this.webSocketService.connect();

     stompClient.connect({}, frame => {

      stompClient.subscribe('/user/queue/notification', notifications => {
               console.log('test'+notifications)
          this.notifications = JSON.parse(notifications.body).count;

      })     });

我已经搜索了许多其他问题并尝试过，但没有一个对我有用例如 here由 Thanh Nguyen Van 和 here 回答

控制台

 Opening Web Socket...
    stomp.js:134 Web Socket Opened...
    stomp.js:134 >>> CONNECT
    accept-version:1.1,1.0
    heart-beat:10000,10000


    stomp.js:134 <<< CONNECTED
    version:1.1
    heart-beat:0,0


    stomp.js:134 connected to server undefined
    reminder.component.ts:18 test callsed
    stomp.js:134 >>> SUBSCRIBE
    id:sub-0
    destination:/user/queue/notification

提前致谢。

Answer 1

gerrytan的答案|至Sending message to specific user on Spring Websocket提到了 Web 套接字配置更改，以注册 /user 前缀。在你的情况下，我猜这意味着替换

registry.enableSimpleBroker("/topic", "/queue");

与

registry.enableSimpleBroker("/topic", "/queue", "/user");

他还说在 Controller 中你不需要 /user 前缀，因为它是自动添加的。所以你可以试试这个:

template.convertAndSendToUser(principal.getName(), "/queue/notification", notifications);

还有这个:

template.convertAndSendToUser(principal.getName(), "/user/queue/notification", notifications);

在客户端，您需要提供用于连接服务器的用户名。你可以直接插入:

stompClient.subscribe('/user/naila/queue/notification', ...)

或从标题中获取。但是Markus在 How to send websocket message to concrete user? 上说即使在这里你也不需要用户名，所以它可能像这样工作:

stompClient.subscribe('/user/queue/notification', ...)