java - Spring/RestTemplate - PUT 实体到服务器

Question

请看这个简单的代码:

final String url = String.format("%s/api/shop", Global.webserviceUrl);

RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());

HttpHeaders headers = new HttpHeaders();
headers.set("X-TP-DeviceID", Global.deviceID);
HttpEntity entity = new HttpEntity(headers);

HttpEntity<Shop[]> response = restTemplate.exchange(url, HttpMethod.GET, entity, Shop[].class);
shops = response.getBody();

如您所见，上述代码旨在从服务器获取商店列表(以 json 格式)并将响应映射到 Shop 对象数组。现在我需要 PUT 新商店，例如/api/shop/1。请求实体应与返回的实体具有完全相同的格式。

我是否应该将/1 添加到我的 url，创建新的 Shop 类对象，所有字段都填充我想要放置的值，然后使用 HttpMethod.PUT 进行交换？

请为我澄清一下，我是 Spring 的初学者。代码示例将不胜感激。

[编辑]我很困惑，因为我刚刚注意到方法 RestTemplate.put()。那么，我应该使用哪一个？交换还是 put()？

Answer 1

你可以试试这样的:

    final String url = String.format("%s/api/shop/{id}", Global.webserviceUrl);

    RestTemplate restTemplate = new RestTemplate();
    restTemplate.getMessageConverters().add(new MappingJackson2HttpMessageConverter());

    HttpHeaders headers = new HttpHeaders();
    headers.set("X-TP-DeviceID", Global.deviceID);
    Shop shop= new Shop();
    Map<String, String> param = new HashMap<String, String>();
    param.put("id","10")
    HttpEntity<Shop> requestEntity = new HttpEntity<Shop>(shop, headers);
    HttpEntity<Shop[]> response = restTemplate.exchange(url, HttpMethod.PUT, requestEntity, Shop[].class, param);

    shops = response.getBody();

put 返回 void 而 exchange 会给你一个响应，最好的检查位置是文档 https://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/web/client/RestTemplate.html