java - 通过注解使用 Hibernate UUIDGenerator

Question

我正在使用我的 uuid，如下所示:

@Id
@GeneratedValue(generator = "uuid")
@GenericGenerator(name = "uuid", strategy = "uuid")
@Column(name = "uuid", unique = true)
private String uuid;

但我收到了智能 hibernate 警告:

Using org.hibernate.id.UUIDHexGenerator which does not generate IETF RFC 4122 compliant UUID values; consider using org.hibernate.id.UUIDGenerator instead

所以我想切换到 org.hibernate.id.UUIDGenerator，现在我的问题是我应该如何告诉 Hibernate 的生成器。我看到有人将它用作“hibernate-uuid” - 所以这是我尝试过的，但结果是否定的:

@Id
@GeneratedValue(generator = "hibernate-uuid")
@GenericGenerator(name = "hibernate-uuid", strategy = "hibernate-uuid")
@Column(name = "uuid", unique = true)
private String uuid;

Answer 1

应该是uuid2:

...
@GenericGenerator(name = "uuid", strategy = "uuid2")
...

见 5.1.2.2.1. Various additional generators .