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java - 没有 [javax.persistence.EntityManager] 类型的限定 bean

转载 作者:IT老高 更新时间:2023-10-28 13:51:20 53 4
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我正在尝试构建一个全新的 Spring Framework 4.0 项目,没有所有神奇的 gradle 东西,只是简单地把它踢过老派。

我正在学习这里的教程:http://spring.io/guides/tutorials/data/并且取得了一些成功。我只是卡在这一点上。

/**
*
*/
package com.corrisoft.air.db.integration;

import javax.persistence.EntityManager;

import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.test.context.ContextConfiguration;
import org.springframework.test.context.junit4.SpringJUnit4ClassRunner;
import org.springframework.test.context.transaction.TransactionConfiguration;
import org.springframework.transaction.annotation.Transactional;

import com.corrisoft.air.db.JPAConfiguration;

import static com.corrisoft.air.db.fixture.JPAAssertions.assertTableExists;
import static com.corrisoft.air.db.fixture.JPAAssertions.assertTableHasColumn;

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(classes = { JPAConfiguration.class })
@Transactional
@TransactionConfiguration(defaultRollback = true)
public class PersonMappingIntegrationTests {

@Autowired
EntityManager manager;

@Test
public void thatItemCustomMappingWorks() throws Exception {
assertTableExists(manager, "PERSONS");

assertTableHasColumn(manager, "PERSONS", "FIRST_NAME");
assertTableHasColumn(manager, "PERSONS", "LAST_NAME");
}
}

当我运行这个单元测试时,我得到以下堆栈跟踪:

SEVERE: Caught exception while allowing TestExecutionListener [org.springframework.test.context.support.DependencyInjectionTestExecutionListener@68c884e] to prepare test instance [com.corrisoft.air.db.integration.PersonMappingIntegrationTests@7448bc3d]
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'com.corrisoft.air.db.integration.PersonMappingIntegrationTests': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: javax.persistence.EntityManager com.corrisoft.air.db.integration.PersonMappingIntegrationTests.manager; nested exception is org.springframework.beans.factory.NoUniqueBeanDefinitionException: No qualifying bean of type [javax.persistence.EntityManager] is defined: expected single matching bean but found 2: entityManager,org.springframework.orm.jpa.SharedEntityManagerCreator#0
at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor.postProcessPropertyValues(AutowiredAnnotationBeanPostProcessor.java:292)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1185)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.autowireBeanProperties(AbstractAutowireCapableBeanFactory.java:384)
at org.springframework.test.context.support.DependencyInjectionTestExecutionListener.injectDependencies(DependencyInjectionTestExecutionListener.java:110)
at org.springframework.test.context.support.DependencyInjectionTestExecutionListener.prepareTestInstance(DependencyInjectionTestExecutionListener.java:75)
at org.springframework.test.context.TestContextManager.prepareTestInstance(TestContextManager.java:326)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.createTest(SpringJUnit4ClassRunner.java:212)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner$1.runReflectiveCall(SpringJUnit4ClassRunner.java:289)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.methodBlock(SpringJUnit4ClassRunner.java:291)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:232)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.runChild(SpringJUnit4ClassRunner.java:89)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:238)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:63)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:236)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:53)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:229)
at org.springframework.test.context.junit4.statements.RunBeforeTestClassCallbacks.evaluate(RunBeforeTestClassCallbacks.java:61)
at org.springframework.test.context.junit4.statements.RunAfterTestClassCallbacks.evaluate(RunAfterTestClassCallbacks.java:71)
at org.junit.runners.ParentRunner.run(ParentRunner.java:309)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:175)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
Caused by: org.springframework.beans.factory.BeanCreationException: Could not autowire field: javax.persistence.EntityManager com.corrisoft.air.db.integration.PersonMappingIntegrationTests.manager; nested exception is org.springframework.beans.factory.NoUniqueBeanDefinitionException: No qualifying bean of type [javax.persistence.EntityManager] is defined: expected single matching bean but found 2: entityManager,org.springframework.orm.jpa.SharedEntityManagerCreator#0
at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:508)
at org.springframework.beans.factory.annotation.InjectionMetadata.inject(InjectionMetadata.java:87)
at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor.postProcessPropertyValues(AutowiredAnnotationBeanPostProcessor.java:289)
... 26 more
Caused by: org.springframework.beans.factory.NoUniqueBeanDefinitionException: No qualifying bean of type [javax.persistence.EntityManager] is defined: expected single matching bean but found 2: entityManager,org.springframework.orm.jpa.SharedEntityManagerCreator#0
at org.springframework.beans.factory.support.DefaultListableBeanFactory.doResolveDependency(DefaultListableBeanFactory.java:967)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.resolveDependency(DefaultListableBeanFactory.java:855)
at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:480)
... 28 more

根据观察和研究,它似乎告诉我有两个 EntityManager 类。第一个来自hibernate JPA jar,但找不到第二个。它似乎告诉我它在 Spring ORM 中,但该类中没有定义。

这是测试中使用的 JPAConfiguration 类:

/**
*
*/
package com.corrisoft.air.db;

import java.sql.SQLException;

import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.sql.DataSource;

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;
import org.springframework.context.annotation.FilterType;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;
import org.springframework.jdbc.datasource.embedded.EmbeddedDatabaseBuilder;
import org.springframework.jdbc.datasource.embedded.EmbeddedDatabaseType;
import org.springframework.orm.hibernate4.HibernateExceptionTranslator;
import org.springframework.orm.jpa.JpaTransactionManager;
import org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean;
import org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter;
import org.springframework.transaction.PlatformTransactionManager;
import org.springframework.transaction.annotation.EnableTransactionManagement;

import com.corrisoft.air.db.repository.PersonsRepository;

/**
* @author Corrisoft Android Development
*
*/
@Configuration
@EnableJpaRepositories(basePackages = "com.corrisoft.db.repository", includeFilters = @ComponentScan.Filter(value = { PersonsRepository.class }, type = FilterType.ASSIGNABLE_TYPE))
@EnableTransactionManagement
public class JPAConfiguration {

@Bean
public DataSource dataSource() throws SQLException {
EmbeddedDatabaseBuilder builder = new EmbeddedDatabaseBuilder();
return builder.setType(EmbeddedDatabaseType.H2).build();
}

@Bean
public EntityManagerFactory entityManagerFactory() throws SQLException {

HibernateJpaVendorAdapter vendorAdapter = new HibernateJpaVendorAdapter();
vendorAdapter.setGenerateDdl(true);

LocalContainerEntityManagerFactoryBean factory = new LocalContainerEntityManagerFactoryBean();
factory.setJpaVendorAdapter(vendorAdapter);
factory.setPackagesToScan("com.corrisoft.air.model");
factory.setDataSource(dataSource());
factory.afterPropertiesSet();

return factory.getObject();
}

@Bean
public EntityManager entityManager(EntityManagerFactory entityManagerFactory) {
return entityManagerFactory.createEntityManager();
}

@Bean
public PlatformTransactionManager transactionManager() throws SQLException {
JpaTransactionManager txManager = new JpaTransactionManager();
txManager.setEntityManagerFactory(entityManagerFactory());
return txManager;
}

@Bean
public HibernateExceptionTranslator hibernateExceptionTranslator() {
return new HibernateExceptionTranslator();
}
}

最佳答案

EntityManager接口(interface)属于JPA,由JPA提供者(如Eclipse)实现,不是Spring,它有自己的注入(inject)注解:@PersistenceContextEntityManager 对象是事务范围的,不应像您正在做的那样公开为 bean。相反,要么使用 JPA 注释来注入(inject) EntityManager:

@PersistenceContext
EntityManager em;

或者,由于您似乎正在尝试使用 Spring 存储库,请改为注入(inject)存储库:

@Autowired
PersonRepository pr;

关于java - 没有 [javax.persistence.EntityManager] 类型的限定 bean,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22301426/

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