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java - 编码密码看起来不像 BCrypt

转载 作者:IT老高 更新时间:2023-10-28 13:50:21 26 4
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我正在使用 Spring Boot、Spring Security、OAuth2 和 JWT 来验证我的应用程序,但我不断收到这个令人讨厌的错误,我不知道出了什么问题。我的 CustomDetailsS​​ervice 类:

@Service
public class CustomDetailsService implements UserDetailsService {

private static final Logger logger = LoggerFactory.getLogger(CustomDetailsService.class);

@Autowired
private UserBO userBo;

@Autowired
private RoleBO roleBo;

@Override
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
AppUsers appUsers = null;
try {
appUsers = this.userBo.loadUserByUsername(username);
System.out.println("========|||=========== "+appUsers.getUsername());
}catch(IndexOutOfBoundsException e){
throw new UsernameNotFoundException("Wrong username");
}catch(DataAccessException e){
e.printStackTrace();
throw new UsernameNotFoundException("Database Error");
}catch(Exception e){
e.printStackTrace();
throw new UsernameNotFoundException("Unknown Error");
}

if(appUsers == null){
throw new UsernameNotFoundException("Bad credentials");
}
logger.info("Username: "+appUsers.getUsername());
return buildUserFromUserEntity(appUsers);
}

private User buildUserFromUserEntity(AppUsers authUsers) {
Set<UserRole> userRoles = authUsers.getUserRoles();

boolean enabled = true;
boolean accountNotExpired = true;
boolean credentialsNotExpired = true;
boolean accountNotLocked = true;

if (authUsers.getAccountIsActive()) {
try {
if(authUsers.getAccountExpired()){
accountNotExpired = true;
} else if (authUsers.getAccountIsLocked()) {
accountNotLocked = true;
} else {
if (containsRole((userRoles), roleBo.findRoleByName("FLEX_ADMIN"))){
accountNotLocked = false;
}
}
}catch(Exception e){
enabled = false;
e.printStackTrace();
}
}else {
accountNotExpired = false;
}
// convert model user to spring security user
String username = authUsers.getUsername();
String password = authUsers.getPassword();

List<GrantedAuthority> authorities = buildUserAuthority(userRoles);

User springUser = new User(username, password,enabled, accountNotExpired, credentialsNotExpired, accountNotLocked, authorities);
return springUser;
}
}

OAuth2Config:

@Configuration
public class OAuth2Config extends AuthorizationServerConfigurerAdapter {

@Autowired
private AuthenticationManager authenticationManager;

@Bean
public JwtAccessTokenConverter tokenConverter() {
JwtAccessTokenConverter tokenConverter = new JwtAccessTokenConverter();
tokenConverter.setSigningKey(PRIVATE_KEY);
tokenConverter.setVerifierKey(PUBLIC_KEY);
return tokenConverter;
}

@Bean
public JwtTokenStore tokenStore() {
return new JwtTokenStore(tokenConverter());
}

@Override
public void configure(AuthorizationServerEndpointsConfigurer endpointsConfigurer) throws Exception {
endpointsConfigurer.authenticationManager(authenticationManager)
.tokenStore(tokenStore())
.accessTokenConverter(tokenConverter());
}

@Override
public void configure(AuthorizationServerSecurityConfigurer securityConfigurer) throws Exception {
securityConfigurer.tokenKeyAccess("permitAll()").checkTokenAccess("isAuthenticated()");
}

@Override
public void configure(ClientDetailsServiceConfigurer clients) throws Exception {
clients.inMemory()
.withClient(CLIENT_ID)
.secret(CLIENT_SECRET)
.scopes("read","write")
.authorizedGrantTypes("password","refresh_token")
.accessTokenValiditySeconds(20000)
.refreshTokenValiditySeconds(20000);
}
}

SecurityConfig:

@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {

@Autowired
CustomDetailsService customDetailsService;

@Bean
public PasswordEncoder encoder() {
return new BCryptPasswordEncoder();
}

@Override
@Autowired
protected void configure(AuthenticationManagerBuilder authenticationManagerBuilder) throws Exception {
authenticationManagerBuilder.userDetailsService(customDetailsService).passwordEncoder(encoder());
System.out.println("Done...finito");
}

@Override
protected void configure(HttpSecurity httpSecurity) throws Exception {
httpSecurity.authorizeRequests()
.anyRequest()
.authenticated()
.and()
.sessionManagement()
.sessionCreationPolicy(SessionCreationPolicy.NEVER);
}

@Override
@Bean
public AuthenticationManager authenticationManager() throws Exception {
return super.authenticationManagerBean();
}
}

没有错误信息,除了:

Hibernate: select appusers0_.id as id1_2_, appusers0_.account_expired as account_2_2_, appusers0_.account_is_active as account_3_2_, appusers0_.account_is_locked as account_4_2_, appusers0_.bank_acct as bank_acc5_2_, appusers0_.branch_id as branch_i6_2_, appusers0_.bvn as bvn7_2_, appusers0_.create_date as create_d8_2_, appusers0_.created_by as created_9_2_, appusers0_.email as email10_2_, appusers0_.email_verified_code as email_v11_2_, appusers0_.gender as gender12_2_, appusers0_.gravatar_url as gravata13_2_, appusers0_.is_deleted as is_dele14_2_, appusers0_.lastname as lastnam15_2_, appusers0_.middlename as middlen16_2_, appusers0_.modified_by as modifie17_2_, appusers0_.modified_date as modifie18_2_, appusers0_.orgnization_id as orgniza19_2_, appusers0_.password as passwor20_2_, appusers0_.phone_no as phone_n21_2_, appusers0_.surname as surname22_2_, appusers0_.token_expired as token_e23_2_, appusers0_.username as usernam24_2_ from users appusers0_ where appusers0_.username=?
Tinubu
2018-03-31 01:42:03.255 INFO 4088 --- [nio-8072-exec-2] o.a.c.c.C.[Tomcat].[localhost].[/] : Initializing Spring FrameworkServlet 'dispatcherServlet'
2018-03-31 01:42:03.255 INFO 4088 --- [nio-8072-exec-2] o.s.web.servlet.DispatcherServlet : FrameworkServlet 'dispatcherServlet': initialization started
2018-03-31 01:42:03.281 INFO 4088 --- [nio-8072-exec-2] o.s.web.servlet.DispatcherServlet : FrameworkServlet 'dispatcherServlet': initialization completed in 26 ms
2018-03-31 01:42:03.489 WARN 4088 --- [nio-8072-exec-2] o.s.s.c.bcrypt.BCryptPasswordEncoder : Encoded password does not look like BCrypt

我的实体模型类是:

@Entity
@Table(name="USERS")
@DynamicUpdate
public class AppUsers {

@Id
@Column(name="ID")
@GeneratedValue(strategy = GenerationType.IDENTITY)
@ApiModelProperty(notes = "The user auto generated identity", required = true)
private Long id;

@Column(name="username")
@ApiModelProperty(notes = "The username parameter", required = true)
private String username;

@Column(name="password")
@ApiModelProperty(notes = "The password parameter", required = true)
private String password;

@JsonManagedReference
@OneToMany(mappedBy="appUsers")
private Set<UserRole> userRoles;

'''''' setters and getters
}

角色实体:

@Entity
@Table(name="ROLE")
public class Role {

@javax.persistence.Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "role_id", unique = true, nullable = false)
private Long Id;

@Column(name = "name")
private String roleName;

@JsonManagedReference
@OneToMany(mappedBy="role")
private Set<UserRole> userRoles;

//getters and setters

}

UserRole 实体:

@Entity
@Table(name="USER_ROLE")
@DynamicUpdate
public class UserRole implements Serializable {

private static final long serialVersionUID = 6128016096756071383L;

@Id
@Column(name="ID")
@GeneratedValue(strategy = GenerationType.IDENTITY)
@ApiModelProperty(notes = "The userrole auto generated identity", required = true)
private long id;

@JsonBackReference
@ManyToOne//(fetch=FetchType.LAZY)
private AppUsers appUsers;

@JsonBackReference
@ManyToOne//(fetch=FetchType.LAZY)
private Role role;

// getters and setters
}

我在数据库中的密码是正确加密的 Spring security BCrypt 并且它的数据类型是大于 60 的 varchar(255)。

最佳答案

BCryptPasswordEncoder 在无法将原始密码与编码密码匹配时显示此警告。

哈希密码现在可能是“$2b”或“$2y”。

Spring Security 中有一个错误,它的正则表达式总是在寻找“$2a”。在 BCryptPasswordEncoder.class 中的 matches() 函数处放置一个调试点。

关于java - 编码密码看起来不像 BCrypt,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49582971/

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