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java - 没有 Spring Boot 的 Spring Data JPA

转载 作者:IT老高 更新时间:2023-10-28 13:45:44 26 4
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Spring Boot 不适用于 Google App Engine(至少不适合我)。

无论 GitHub 或其他存储库中编写或提供的许多示例都使用 Spring Boot,是否有任何不使用 Spring Boot 并使用纯上下文 XML 的 Spring-Data-JPA 示例和以前一样?

这会显示

-spring/context.xml(或servlet-context.xml)

最佳答案

刚刚为您创建了这个示例:

src/main/webapp/WEB-INF/spring/context.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:jpa="http://www.springframework.org/schema/data/jpa"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa.xsd">

<context:property-placeholder location="/WEB-INF/spring/jdbc.properties" />

<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
p:driverClassName="${jdbc.driverClassName}" p:url="${jdbc.url}"
p:username="${jdbc.username}" p:password="${jdbc.password}" />

<bean id="hibernateJpaVendorAdapter"
class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />

<!-- Configure the entity manager factory bean -->
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="jpaVendorAdapter" ref="hibernateJpaVendorAdapter" />
<!-- Set JPA properties -->
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">${hibernate.dialect}</prop>
</props>
</property>
<property name="packagesToScan" value="com.demo.data" />
</bean>

<!-- Configure the transaction manager bean -->
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>

<tx:annotation-driven />

<jpa:repositories base-package="com.demo.data" />
<context:component-scan base-package="com.demo.svc" />
</beans>

/src/main/webapp/WEB-INF/spring/jdbc.properties

# JDBC Connection
jdbc.driverClassName=com.mysql.jdbc.Driver
jdbc.url=jdbc:mysql://host:3306/db
jdbc.username=user
jdbc.password=password
hibernate.dialect=org.hibernate.dialect.MySQLDialect

/src/main/webapp/WEB-INF/spring/servlet-context.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

<context:component-scan base-package="com.demo.web" />
</beans:beans>

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/context.xml</param-value>
</context-param>
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>demo_jpa</param-value>
</context-param>

<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>

pom.xml

<properties>
<org.springframework-version>4.1.7.RELEASE</org.springframework-version>
<org.hibernate-em-version>4.3.8.Final</org.hibernate-em-version>
<org.springframework.data-version>1.9.0.RELEASE</org.springframework.data-version>
<dbcp-version>1.4</dbcp-version>
<mysql-connector-version>5.1.28</mysql-connector-version>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>

<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context-support</artifactId>
<version>${org.springframework-version}</version>
</dependency>

<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-webmvc</artifactId>
<version>${org.springframework-version}</version>
</dependency>

<dependency>
<groupId>org.springframework.data</groupId>
<artifactId>spring-data-jpa</artifactId>
<version>${org.springframework.data-version}</version>
</dependency>

<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-entitymanager</artifactId>
<version>${org.hibernate-em-version}</version>
</dependency>

<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<version>${mysql-connector-version}</version>
</dependency>

<dependency>
<groupId>commons-dbcp</groupId>
<artifactId>commons-dbcp</artifactId>
<version>${dbcp-version}</version>
</dependency>
</dependencies>

数据实体:com.demo.data.User

package com.demo.data;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name = "SYS_USERS")
public class User {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "USER_ID")
private int id;

@Column(name = "USER_NAME")
private String name;

public int getId() {
return id;
}

public void setId(int id) {
this.id = id;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}
}

Spring Data JPA 存储库:com.demo.data.UserRepository

package com.demo.data;

import org.springframework.data.repository.CrudRepository;

public interface UserRepository extends CrudRepository<User, Integer> {
}

服务

界面:

package com.demo.svc;

import com.demo.data.User;

public interface UserService {
User findUserById(Integer id);
}

实现:

package com.demo.svc;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;

import com.demo.data.User;
import com.demo.data.UserRepository;

@Service
public class UserServiceImpl implements UserService {
@Autowired
UserRepository userRepository;

public User findUserById(Integer id) {
return userRepository.findOne(id);
}
}

网页 Controller :com.demo.web.UserController

package com.demo.web;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.ResponseBody;

import com.demo.svc.UserService;

@Controller
public class UserController {
@Autowired
UserService svc;

@RequestMapping("/")
@ResponseBody
public String test() {
return svc.findUserById(1).getName();
}
}

关于java - 没有 Spring Boot 的 Spring Data JPA,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23974249/

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