java - 验证失败时在 Spring RestController 中抛出什么类型的异常？

Question

在 Spring RestController 中，我只需将相应的方法参数注释为 @Valid 或 即可对 RequestBody 进行输入验证@Validated。其他一些验证只能在对传入数据进行一些处理后执行。我的问题是，我应该使用什么类型的异常，以便它类似于 @Valid 注释抛出的异常，以及如何从验证结果构造这个异常。这是一个例子:

@RequestMapping(method = RequestMethod.POST)
public ResponseEntity<?> createOrder(@RequestBody @Validated(InputChecks.class) Order order) {
    // Some processing of the Order goes here
    Set<ConstraintViolation<Order>> violations = validator.validate(order, FinalChecks.class);
    // What to do now with the validation errors?
    orders.put(order);
    HttpHeaders headers = new HttpHeaders();
    headers.setLocation(ServletUriComponentsBuilder.fromCurrentRequest().path("/" + order.getId()).build().toUri());
    return new ResponseEntity<>(null, headers, HttpStatus.CREATED);
}

Answer 1

对我来说，最简单的方法是使用错误对象验证对象，然后在 MethodArgumentNotValidException 中使用它。

@RequestMapping(method = RequestMethod.POST)
public ResponseEntity<?> createOrder(@RequestBody @Validated(InputChecks.class) Order order)
                throws NoSuchMethodException, SecurityException, MethodArgumentNotValidException {
    // Some processing of the Order goes here
    SpringValidatorAdapter v = new SpringValidatorAdapter(validator);
    BeanPropertyBindingResult errors = new BeanPropertyBindingResult(order, "order");
    v.validate(order, errors, FinalChecks.class);
    if (errors.hasErrors()) {
        throw new MethodArgumentNotValidException(
                new MethodParameter(this.getClass().getDeclaredMethod("createOrder", Order.class), 0),
                errors);
    }
    orders.put(order);
    HttpHeaders headers = new HttpHeaders();
    headers.setLocation(ServletUriComponentsBuilder.fromCurrentRequest().path("/" + order.getId()).build().toUri());
    return new ResponseEntity<>(null, headers, HttpStatus.CREATED);
}

这样，在第二个验证步骤中发现的错误与在@validated 参数的输入验证过程中发现的错误具有完全相同的结构。