kotlin - 如何在匿名类中引用自己？

Question

我在 kotlin 中有下一个代码:

handler.postDelayed(object : Runnable {
            override fun run() {
                Timber.i("run post msg")
                handler.postDelayed(this, AppPrefs.SEARCH_DELAY)
            }
        },AppPrefs.SOCKET_INTERVAL)

您如何看待创建延迟任务的简单标准方法(使用 Runnable class)。值 this 引用 anonimus 对象实现 Runnable 并编译并正常工作

但是当我为此制作 lamdba 时:

handler.postDelayed({
            Timber.i("run post msg")
            handler.postDelayed(this, AppPrefs.SOCKET_INTERVAL)
        },AppPrefs.SOCKET_INTERVAL)

value this 引用了外部类。

如何从内部匿名类引用到你自己？

Answer 1

你不能这样做。一个 similar question在 Kotlin 的论坛上被问到，yole(该语言的创造者之一)这样说:

this in a lambda refers to the instance of the containing class, if any. A lambda is conceptually a function, not a class, so there is no such thing as a lambda instance to which this could refer.

The fact that a lambda can be converted into an instance of a SAM interface does not change this. Having this in a lambda mean different things depending on whether the lambda gets SAM-converted would be extremely confusing.