java - MongoDb 通过 jndi

Question

您知道是否可以像其他任何数据库一样通过来自 jndi 的数据源在 spring 中设置 mongodb 实例？

谢谢

Answer 1

是的，有可能，当您可以创建自己的 JNDI 工厂时，为什么还要依赖其他人的代码？只需创建一个实现 javax.naming.spi.ObjectFactory 的类和一个从 JNDI 上下文中提取 mongo 的 bean，我为 spring data-mongo MongoTemplate 对象配置了它。

public class CustomMongoJNDIFactory implements ObjectFactory {

public Object getObjectInstance(Object obj, Name name, Context nameCtx,
        Hashtable<?, ?> environment) throws Exception {

    validateProperty(obj, "Invalid JNDI object reference");

    MongoTemplate mongoTemplate = null;
    String db = null;
    String host = null;
    String username = null;
    String password = null;
    int port = 27017;

    Reference ref = (Reference) obj;
    Enumeration<RefAddr> props = ref.getAll();
    while (props.hasMoreElements()) {
        RefAddr addr = (RefAddr) props.nextElement();
        String propName = addr.getType();
        String propValue = (String) addr.getContent();
        if (propName.equals("db")) {
            db = propValue;
        } else if (propName.equals("host")) {
            host = propValue;
        } else if (propName.equals("username")) {
            username = propValue;
        } else if (propName.equals("password")) {
            password = propValue;
        } else if (name.equals("port")) {
            try {
                port = Integer.parseInt(propValue);
            } catch (NumberFormatException e) {
                throw new NamingException("Invalid port value " + propValue);
            }
        }

    }

    // validate properties
    validateProperty(db, "Invalid or empty mongo database name");
    validateProperty(host, "Invalid or empty mongo host");
    validateProperty(username, "Invalid or empty mongo username");
    validateProperty(password, "Invalid or empty mongo password");

    //create mongo template
    mongoTemplate = new MongoTemplate(new Mongo(host, port), db,
            new UserCredentials(username, password));

    return mongoTemplate;
}


/**
 * Validate internal String properties
 * 
 * @param property
 * @param errorMessage
 * @throws NamingException
 */
private void validateProperty(String property, String errorMessage)
        throws NamingException {
    if (property == null || property.trim().equals("")) {
        throw new NamingException(errorMessage);
    }
}

/**
 * Validate internal Object properties
 * 
 * @param property
 * @param errorMessage
 * @throws NamingException
 */
private void validateProperty(Object property, String errorMessage)
        throws NamingException {
    if (property == null) {
        throw new NamingException(errorMessage);
    }
}

}

Spring Bean :

@Configuration
@Qualifier("mongoTemplate")
public class CustomMongoTemplate  {


 public @Bean MongoTemplate mongoTemplate() throws Exception {
     Context initCtx = new InitialContext();
     Context envCtx = (Context) initCtx.lookup("java:comp/env");
     return (MongoTemplate) envCtx.lookup("bean/MyMongoBean");
    }
}

上下文.xml:

<Resource name="bean/MyMongoBean" auth="Container"
        type="org.springframework.data.mongodb.core.MongoTemplate"
        factory="com.package.CustomMongoJNDIFactory"
        host="" db="" username="" password=""/>

Web.xml

    <resource-env-ref>
    <description>Mongo JNDI configuration</description>
    <resource-env-ref-name>comp/env/bean/MyMongoBean</resource-env-ref-name>
    <resource-env-ref-type>org.springframework.data.mongodb.core.MongoTemplate</resource-env-ref-type>
</resource-env-ref>