java - 防止 ProGuard 混淆类成员名称

Question

我的类 ClassMultiPoint 有子类。

public class ClassMultiPoints
 {
   public String message;
   public List<ClassPoints> data;

   public class ClassPoints
    {
      public String id;
      public List<ClassPoint> points;
      public class ClassPoint
       {
         public String speed;
         public String bearing;
       }
    }
 }

我将从解析 GSON 中获取对象 oPoints 的值:

oPoints = gson.fromJson(jsonString, ClassMultiPoints.class);

我尝试使用 oPoints.message。

当我在没有 proguard 的情况下运行我的应用程序时，应用程序运行成功。当我使用 proguard 运行我的应用程序时，我的应用程序崩溃了。

我认为问题是:proguard 将我的类(class)的属性 'oPoints.message' 重命名为短 'a'。

我尽量保持方法和属性的名称不变，但是 proguard 重命名它:

proguard.cfg:

-injars      bin/classes
-injars      libs
-outjars     bin/classes-processed.jar
-dontpreverify
-repackageclasses ''
-allowaccessmodification
-optimizations !code/simplification/arithmetic
-keepattributes *Annotation*
-dontskipnonpubliclibraryclasses
-optimizationpasses 5
-printmapping map.txt
-flattenpackagehierarchy

-keep public class * extends android.app.Activity
-keep public class * extends android.app.Application
-keep public class * extends android.app.MapActivity
-keep public class * extends android.app.Service
-keep public class * extends android.content.BroadcastReceiver
-keep public class * extends android.content.ContentProvider

-libraryjars  libs/commons-io-2.2.jar
-libraryjars  libs/ftp4j-1.7.1.jar
-libraryjars  libs/gson-2.2.2.jar

-keep public class org.apache.commons.io.**
-keep public class it.sauronsoftware.ftp4j.**
-keep public class com.google.gson.**

-keep public class com.mypackagename.ActivityMonitor$*

-keep public class * extends android.view.View {
    public <init>(android.content.Context);
    public <init>(android.content.Context, android.util.AttributeSet);
    public <init>(android.content.Context, android.util.AttributeSet, int);
    public void set*(...);
}

-keepclasseswithmembers class * {
    public <init>(android.content.Context, android.util.AttributeSet);
}

-keepclasseswithmembers class * {
    public <init>(android.content.Context, android.util.AttributeSet, int);
}

-keepclassmembers class * extends android.content.Context {
   public void *(android.view.View);
   public void *(android.view.MenuItem);
}

-keepclassmembers class * implements android.os.Parcelable {
    static android.os.Parcelable$Creator CREATOR;
}

-keepclassmembers class **.R$* {
    public static <fields>;
}

保留我的一个(静态)类的方法和属性名称的正确方法是什么？

Answer 1

如果您不希望您的类成员被混淆，请使用 Gson 提供的 SerializedName 注释。例如:

public class ClassMultiPoints
{
   @SerializedName("message")
   public String message;
   @SerializedName("data")
   public List<ClassPoints> data;

   ...

}

此外，请确保您也为 Gson 库添加了正确的 proguard 配置。例如:

##---------------Begin: proguard configuration for Gson ----------
# Gson uses generic type information stored in a class file when working with
#fields. Proguard removes such information by default, so configure it to keep
#all of it.
-keepattributes Signature

# For using GSON @Expose annotation
-keepattributes *Annotation*

# Gson specific classes
-keep class sun.misc.Unsafe { *; }
#-keep class com.google.gson.stream.** { *; }

# Application classes that will be serialized/deserialized over Gson
-keep class com.google.gson.examples.android.model.** { *; }

##---------------End: proguard configuration for Gson ----------

更多信息请阅读 this .