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MongoDB 聚合展开多个数组

转载 作者:IT老高 更新时间:2023-10-28 13:16:09 29 4
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这就是我的文档的样子

{
code: "A2df",
clicks: 7,
countries: [{"country":"IN", clicks:5},{"country":"US", clicks:2}],
domains: [{"domain":"a.com", clicks:4},{"country":"b.com", clicks:3}]
},
{
code: "B3ws",
clicks: 11,
countries: [{"country":"IN", clicks:6},{"country":"ND", clicks:5}],
domains: [{"domain":"a.com", clicks:7},{"country":"c.com", clicks:4}]
},
{
code: "A2df",
clicks: 5,
countries: [{"country":"IN", clicks:2},{"country":"ND", clicks:3}],
domains: [{"domain":"a.com", clicks:1},{"country":"c.com", clicks:4}]
}...

这是我需要的:

{
code: "A2df",
clicks: 12,
countries: [
{
"country": "IN",
clicks: 7
},
{
"country": "US",
clicks: 2
},
{
"country": "ND",
clicks: 3
}
],
domains: [
{
"domain": "a.com",
clicks: 5
},
{
"country": "b.com",
clicks: 3
},
{
"country": "c.com",
clicks: 4
}
]
}

我知道如何在多个查询中执行此操作。我可以对点击进行组聚合和求和,展开数组,然后对它们进行分组,然后对它们求和。但是我想跳过向数据库发出三个请求然后合并三个结果的痛苦。

在 MongoDB 中是否有一种方法可以在单个查询中完成所有这些操作。我无法更改文档的结构。任何帮助表示赞赏。即使这不能在单个查询中完成,任何建议都可以减轻痛苦。 :)

这是我迄今为止尝试让它在单个查询中工作的方法:

[
{
$match: {
date: {
$gte: fromDate,
$lt: toDate
},
brand_id: brandId,
type: "item"
}
},
{
$unwind: "$countries"
},
{
$group: {
_id: {
code: "$code",

},
clicks: {
$sum: "$countries.clicks"
},
countries: {
$push: "$countries"
}
}
},
{
$unwind: "$domains"
},
{
$group: {
_id: {
code: "$code",

},
clicks: {
$sum: "$domains.clicks"
},
domains: {
$push: "$domains"
}
}
}
]

这将返回一个空数组,但如果我只是进行第一次展开和分组,它会为我提供国家/地区所需的输出。这就是我要解决的问题,尝试在一个查询中获取所有内容。

最佳答案

db.test.aggregate([
// Summarize clicks and collect countries and domains for each code
{
$group: {
_id: "$code",
clicks: { $sum: "$clicks" },
countries: { $push: "$countries" },
domains: { $push: "$domains" },
}
},
// Unwind array of array of sub-countries
{
$unwind: "$countries"
},
// Unwind each array of sub-countries
{
$unwind: "$countries"
},
// Summarize clicks for each sub-country
{
$group: {
_id: { code: "$_id", country: "$countries.country"},
clicks: { $min: "$clicks" }, // Keep clicks which we've summarized into the 1st $group
countryClick: { $sum: "$countries.clicks" },
domains: { $first: "$domains" }, // Keep domains
}
},
// Collect sub-countries into embedded document
{
$group: {
_id: "$_id.code",
clicks: { $min: "$clicks" }, // Keep clicks which we've summarized into the 1st $group
countries: { $push: { country: "$_id.country", clicks: "$countryClick" } },
domains: { $first: "$domains" }, // Keep sub-domains
}
},
// Unwind array of array of sub-domains
{
$unwind: "$domains"
},
// Unwind each array of sub-domains
{
$unwind: "$domains"
},
// Summarize clicks for each sub-domain
{
$group: {
_id: { code: "$_id", domain: "$domains.domain", country: "$domains.country" },
clicks: { $min: "$clicks" }, // Keep clicks which we've summarized into the 1st $group
domainClick: { $sum: "$domains.clicks" },
countries: { $first: "$countries" }, // Keep sub-countries
}
},
// Collect sub-domains into embedded document
{
$group: {
_id: "$_id.code",
clicks: { $min: "$clicks" }, // Keep clicks which we've summarized into the 1st $group
domains: { $push: { domain: "$_id.domain", country: "$_id.country", clicks: "$domainClick" } },
countries: { $first: "$countries" }, // Keep sub-countries
}
},
]).pretty()

关于MongoDB 聚合展开多个数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29195272/

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