go - new() 和 "regular"分配有区别吗？

Question

在 Go 中，以下两段代码之间是否存在显着差异:

v := &Vector{}

相对

v := new(Vector)

Answer 1

没有。他们返回的都是一样的，

package main

import "fmt"
import "reflect"

type Vector struct {
    x   int
    y   int
}

func main() {
    v := &Vector{}
    x := new(Vector)
    fmt.Println(reflect.TypeOf(v))
    fmt.Println(reflect.TypeOf(x))
}

结果:

*main.Vector
*main.Vector

邮件列表中存在一些争论，认为两者兼有会令人困惑:

https://groups.google.com/forum/?fromgroups=#!topic/golang-nuts/GDXFDJgKKSs

需要注意的一点:

new() is the only way to get a pointer to an unnamed integer or other basic type. You can write "p := new(int)" but you can't write "p := &int{0}". Other than that, it's a matter of preference.

来源:https://groups.google.com/d/msg/golang-nuts/793ZF_yeqbk/-zyUAPT-e4IJ