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c++ - 如何在 Linux 架构上即时列出 C 代码中可用的所有函数/符号?

转载 作者:IT老高 更新时间:2023-10-28 12:59:40 28 4
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假设 main.c 使用来自共享库的符号和在 main.c 中声明的本地函数。

有没有一种优雅优雅的方式在运行时打印所有可用函数名称和符号的列表?

应该可以,因为数据是加载到.code段的。

最佳答案

由于我同样需要在运行时检索所有加载的符号名称,因此我根据 R.. 的回答做了一些研究。所以这里有一个 ELF 格式的 linux 共享库的详细解决方案,它适用于我的 gcc 4.3.4,但希望也适用于较新的版本。

我主要使用以下资源来开发此解决方案:

这是我的代码。我使用 self 解释变量名称并添加了详细的注释以使其易于理解。如果有什么错误或遗漏,请告诉我...(编辑:我刚刚意识到问题是针对 C 的,而我的代码是针对 C++ 的。但是如果您省略了 vector 和字符串,它也应该适用于 C)

#include <link.h>
#include <string>
#include <vector>

using namespace std;

/* Callback for dl_iterate_phdr.
* Is called by dl_iterate_phdr for every loaded shared lib until something
* else than 0 is returned by one call of this function.
*/
int retrieve_symbolnames(struct dl_phdr_info* info, size_t info_size, void* symbol_names_vector)
{

/* ElfW is a macro that creates proper typenames for the used system architecture
* (e.g. on a 32 bit system, ElfW(Dyn*) becomes "Elf32_Dyn*") */
ElfW(Dyn*) dyn;
ElfW(Sym*) sym;
ElfW(Word*) hash;

char* strtab = 0;
char* sym_name = 0;
ElfW(Word) sym_cnt = 0;

/* the void pointer (3rd argument) should be a pointer to a vector<string>
* in this example -> cast it to make it usable */
vector<string>* symbol_names = reinterpret_cast<vector<string>*>(symbol_names_vector);

/* Iterate over all headers of the current shared lib
* (first call is for the executable itself) */
for (size_t header_index = 0; header_index < info->dlpi_phnum; header_index++)
{

/* Further processing is only needed if the dynamic section is reached */
if (info->dlpi_phdr[header_index].p_type == PT_DYNAMIC)
{

/* Get a pointer to the first entry of the dynamic section.
* It's address is the shared lib's address + the virtual address */
dyn = (ElfW(Dyn)*)(info->dlpi_addr + info->dlpi_phdr[header_index].p_vaddr);

/* Iterate over all entries of the dynamic section until the
* end of the symbol table is reached. This is indicated by
* an entry with d_tag == DT_NULL.
*
* Only the following entries need to be processed to find the
* symbol names:
* - DT_HASH -> second word of the hash is the number of symbols
* - DT_STRTAB -> pointer to the beginning of a string table that
* contains the symbol names
* - DT_SYMTAB -> pointer to the beginning of the symbols table
*/
while(dyn->d_tag != DT_NULL)
{
if (dyn->d_tag == DT_HASH)
{
/* Get a pointer to the hash */
hash = (ElfW(Word*))dyn->d_un.d_ptr;

/* The 2nd word is the number of symbols */
sym_cnt = hash[1];

}
else if (dyn->d_tag == DT_STRTAB)
{
/* Get the pointer to the string table */
strtab = (char*)dyn->d_un.d_ptr;
}
else if (dyn->d_tag == DT_SYMTAB)
{
/* Get the pointer to the first entry of the symbol table */
sym = (ElfW(Sym*))dyn->d_un.d_ptr;


/* Iterate over the symbol table */
for (ElfW(Word) sym_index = 0; sym_index < sym_cnt; sym_index++)
{
/* get the name of the i-th symbol.
* This is located at the address of st_name
* relative to the beginning of the string table. */
sym_name = &strtab[sym[sym_index].st_name];

symbol_names->push_back(string(sym_name));
}
}

/* move pointer to the next entry */
dyn++;
}
}
}

/* Returning something != 0 stops further iterations,
* since only the first entry, which is the executable itself, is needed
* 1 is returned after processing the first entry.
*
* If the symbols of all loaded dynamic libs shall be found,
* the return value has to be changed to 0.
*/
return 1;

}

int main()
{
vector<string> symbolNames;
dl_iterate_phdr(retrieve_symbolnames, &symbolNames);

return 0;
}

关于c++ - 如何在 Linux 架构上即时列出 C 代码中可用的所有函数/符号?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15779185/

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