gpt4 book ai didi

mysql - 来自 MySQL 中多个表的 COUNT(*)

转载 作者:IT老高 更新时间:2023-10-28 12:58:34 25 4
gpt4 key购买 nike

如何从 MySQL 的多个表中选择 COUNT(*)?

如:

SELECT COUNT(*) AS table1Count FROM table1 WHERE someCondition
JOIN??
SELECT COUNT(*) AS table2Count FROM table2 WHERE someCondition
CROSS JOIN? subqueries?
SELECT COUNT(*) AS table3Count FROM table3 WHERE someCondition

编辑:

目标是返回这个:

+-------------+-------------+-------------+
| table1Count | table2Count | table3Count |
+-------------+-------------+-------------+
| 14 | 27 | 0 |
+-------------+-------------+-------------+

最佳答案

您可以通过使用子查询来做到这一点,每个 tableCount 一个子查询:

SELECT
(SELECT COUNT(*) FROM table1 WHERE someCondition) as table1Count,
(SELECT COUNT(*) FROM table2 WHERE someCondition) as table2Count,
(SELECT COUNT(*) FROM table3 WHERE someCondition) as table3Count

关于mysql - 来自 MySQL 中多个表的 COUNT(*),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3761240/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com