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jquery - 如何在 jQuery 中使用 json 数据填充下拉列表?

转载 作者:IT老高 更新时间:2023-10-28 12:51:47 25 4
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我正在开发一个国家级联下拉列表...我根据 countryId 返回了 JSON 结果,但我不知道如何将其填充/填充到新的下拉列表框中...

这是我正在使用的,

function getstate(countryId) {
$.ajax({
type: "POST",
url: "Reg_Form.aspx/Getstates",
data: "{'countryId':" + (countryId) + "}",
contentType: "application/json; charset=utf-8",
global: false,
async: false,
dataType: "json",
success: function(jsonObj) {
alert(jsonObj.d);
}
});
return false;
}

alert 给出了这个,

{"Table" : [{"stateid" : "2","statename" : "Tamilnadu"},
{"stateid" : "3","statename" : "Karnataka"},
{"stateid" : "4","statename" : "Andaman and Nicobar"},
{"stateid" : "5","statename" : "Andhra Pradesh"},
{"stateid" : "6","statename" : "Arunachal Pradesh"}]}

我的 aspx 页面有这个,

<td>
<asp:DropDownList ID="DLCountry" runat="server" CssClass="dropDownListSkin"
onchange="return getstate(this.value);">
</asp:DropDownList>
</td>
<td>
<asp:DropDownList ID="DLState" runat="server" CssClass="dropDownListSkin">
</asp:DropDownList>
</td>

关于如何填写 DLState 下拉列表的任何建议...

编辑:

当我通过 firebug 检查时,我收到了我的 AJAX 帖子的响应,

{"d":"{\"Table\" : [{\"stateid\" : \"2\",\"statename\" : \"Tamilnadu\"},{\"stateid\" : \"3\",\"statename\" : \"Karnataka\"},{\"stateid\" : \"4\",\"statename\" : \"Andaman and Nicobar\"},{\"stateid\" : \"5\",\"statename\" : \"Andhra Pradesh\"},{\"stateid\" : \"6\",\"statename\" : \"Arunachal Pradesh\"},{\"stateid\" : \"7\",\"statename\" : \"Assam\"},{\"stateid\" : \"8\",\"statename\" : \"Bihar\"},{\"stateid\" : \"9\",\"statename\" : \"Dadra and N. Haveli\"},{\"stateid\" : \"10\",\"statename\" : \"Daman and Diu\"},{\"stateid\" : \"11\",\"statename\" : \"Delhi\"},{\"stateid\" : \"12\",\"statename\" : \"Goa\"},{\"stateid\" : \"13\",\"statename\" : \"Gujarat\"},{\"stateid\" : \"14\",\"statename\" : \"Haryana\"},{\"stateid\" : \"15\",\"statename\" : \"Himachal Pradesh\"},{\"stateid\" : \"16\",\"statename\" : \"Jammu and Kashmir\"},{\"stateid\" : \"17\",\"statename\" : \"Kerala\"},{\"stateid\" : \"18\",\"statename\" : \"Laccadive Islands\"},{\"stateid\" : \"19\",\"statename\" : \"Madhya Pradesh\"},{\"stateid\" : \"20\",\"statename\" : \"Maharashtra\"},{\"stateid\" : \"21\",\"statename\" : \"Manipur\"},{\"stateid\" : \"22\",\"statename\" : \"Meghalaya\"},{\"stateid\" : \"23\",\"statename\" : \"Mizoram\"},{\"stateid\" : \"24\",\"statename\" : \"Nagaland\"},{\"stateid\" : \"25\",\"statename\" : \"Orissa\"},{\"stateid\" : \"26\",\"statename\" : \"Pondicherry\"},{\"stateid\" : \"27\",\"statename\" : \"Punjab\"},{\"stateid\" : \"28\",\"statename\" : \"Rajasthan\"},{\"stateid\" : \"29\",\"statename\" : \"Sikkim\"},{\"stateid\" : \"30\",\"statename\" : \"Tripura\"},{\"stateid\" : \"31\",\"statename\" : \"Uttar Pradesh\"},{\"stateid\" : \"32\",\"statename\" : \"West Bengal\"}]}"}

最佳答案

var listItems= "";
var jsonData = jsonObj.d;
for (var i = 0; i < jsonData.Table.length; i++){
listItems+= "<option value='" + jsonData.Table[i].stateid + "'>" + jsonData.Table[i].statename + "</option>";
}
$("#<%=DLState.ClientID%>").html(listItems);

示例

   <html>
<head></head>
<body>
<select id="DLState">
</select>
</body>
</html>

/*javascript*/
var jsonList = {"Table" : [{"stateid" : "2","statename" : "Tamilnadu"},
{"stateid" : "3","statename" : "Karnataka"},
{"stateid" : "4","statename" : "Andaman and Nicobar"},
{"stateid" : "5","statename" : "Andhra Pradesh"},
{"stateid" : "6","statename" : "Arunachal Pradesh"}]}

$(document).ready(function(){
var listItems= "";
for (var i = 0; i < jsonList.Table.length; i++){
listItems+= "<option value='" + jsonList.Table[i].stateid + "'>" + jsonList.Table[i].statename + "</option>";
}
$("#DLState").html(listItems);
});

关于jquery - 如何在 jQuery 中使用 json 数据填充下拉列表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2637694/

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