javascript - 处理 d3.js 轴上的日期

Question

如何根据 d3.js 中的日期制作我的线 x 轴？

我正在尝试自学如何使用 d3.js。我一直在查看它附带的示例，并一直在尝试使用 json 传递的数据重新创建折线图。我可以将数据输入折线图，但 x 轴应该是日期而不是数字。我使用的日期格式是 MM/DD/YY，但图表将所有内容都绘制为 0。我的 json 数据很好，但我无法弄清楚如何绘制 x 坐标。这直接取自下载时 d3.js 示例文件夹中的 line.js。日期部分不起作用。我希望有人能给我举个例子，或者能够解释我如何使它起作用。

d3.json('jsonChartData.action',
  function (data) {
    console.log(data);

    var w = 450,
    h = 275,
    p = 30,
    x = d3.scale.linear().domain([0, 100]).range([0, w]),
    y = d3.scale.linear().domain([0, 100]).range([h, 0]);

    var vis = d3.select("body")
    .data([data])
    .append("svg:svg")
    .attr("width", w + p * 2)
    .attr("height", h + p * 2)
    .append("svg:g")
    .attr("transform", "translate(" + p + "," + p + ")");

    var rules = vis.selectAll("g.rule")
    .data(x.ticks(5))
    .enter().append("svg:g")
    .attr("class", "rule");

    rules.append("svg:line")
    .attr("x1", x)
    .attr("x2", x)
    .attr("y1", 0)
    .attr("y2", h - 1);

    rules.append("svg:line")
    .attr("class", function(d) { return d ? null : "axis"; })
    .attr("y1", y)
    .attr("y2", y)
    .attr("x1", 0)
    .attr("x2", w + 1);

    rules.append("svg:text")
    .attr("x", x)
    .attr("y", h + 3)
    .attr("dy", ".71em")
    .attr("text-anchor", "middle")
    .text(x.tickFormat(10));

    rules.append("svg:text")
    .attr("y", y)
    .attr("x", -3)
    .attr("dy", ".35em")
    .attr("text-anchor", "end")
    .text(y.tickFormat(10));

    vis.append("svg:path")
    .attr("class", "line")
    .attr("d", d3.svg.line()
    .x(function(d) { return x(d3.time.days(new Date(d.jsonDate))); })
    .y(function(d) { return y(d.jsonHitCount); }));

    vis.selectAll("circle.line")
    .data(data)
    .enter().append("svg:circle")
    .attr("class", "line")
    .attr("cx", function(d) { return x(d3.time.days(new Date(d.jsonDate))); })
    .attr("cy", function(d) { return y(d.jsonHitCount); })
    .attr("r", 3.5);
  });

我的操作打印出的 JSON:

[{"jsonDate":"09\/22\/11","jsonHitCount":2,"seriesKey":"Website Usage"},`{"jsonDate":"09\/26\/11","jsonHitCount":9,"seriesKey":"Website Usage"},{"jsonDate":"09\/27\/11","jsonHitCount":9,"seriesKey":"Website Usage"},{"jsonDate":"09\/29\/11","jsonHitCount":26,"seriesKey":"Website Usage"},{"jsonDate":"09\/30\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"10\/03\/11","jsonHitCount":3,"seriesKey":"Website Usage"},{"jsonDate":"10\/06\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"10\/11\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"10\/12\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"10\/13\/11","jsonHitCount":1,"seriesKey":"Website Usage"},{"jsonDate":"10\/14\/11","jsonHitCount":5,"seriesKey":"Website Usage"},{"jsonDate":"10\/17\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"10\/18\/11","jsonHitCount":6,"seriesKey":"Website Usage"},{"jsonDate":"10\/19\/11","jsonHitCount":8,"seriesKey":"Website Usage"},{"jsonDate":"10\/20\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"10\/21\/11","jsonHitCount":4,"seriesKey":"Website Usage"},{"jsonDate":"10\/24\/11","jsonHitCount":1,"seriesKey":"Website Usage"},{"jsonDate":"10\/25\/11","jsonHitCount":1,"seriesKey":"Website Usage"},{"jsonDate":"10\/27\/11","jsonHitCount":3,"seriesKey":"Website Usage"},{"jsonDate":"11\/01\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"11\/02\/11","jsonHitCount":1,"seriesKey":"Website Usage"},{"jsonDate":"11\/03\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"11\/04\/11","jsonHitCount":37,"seriesKey":"Website Usage"},{"jsonDate":"11\/08\/11","jsonHitCount":1,"seriesKey":"Website Usage"},{"jsonDate":"11\/10\/11","jsonHitCount":39,"seriesKey":"Website Usage"},{"jsonDate":"11\/11\/11","jsonHitCount":1,"seriesKey":"Website Usage"},{"jsonDate":"11\/14\/11","jsonHitCount":15,"seriesKey":"Website Usage"},{"jsonDate":"11\/15\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"11\/16\/11","jsonHitCount":5,"seriesKey":"Website Usage"},{"jsonDate":"11\/17\/11","jsonHitCount":4,"seriesKey":"Website Usage"},{"jsonDate":"11\/21\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"11\/22\/11","jsonHitCount":3,"seriesKey":"Website Usage"},{"jsonDate":"11\/23\/11","jsonHitCount":11,"seriesKey":"Website Usage"},{"jsonDate":"11\/24\/11","jsonHitCount":2,"seriesKey":"Website Usage"},{"jsonDate":"11\/25\/11","jsonHitCount":1,"seriesKey":"Website Usage"},{"jsonDate":"11\/28\/11","jsonHitCount":10,"seriesKey":"Website Usage"},{"jsonDate":"11\/29\/11","jsonHitCount":3,"seriesKey":"Website Usage"}]`

Answer 1

您正在尝试使用 d3.scale.linear() 作为日期，但这是行不通的。您需要改用 d3.time.scale() (docs):

// helper function
function getDate(d) {
    return new Date(d.jsonDate);
}

// get max and min dates - this assumes data is sorted
var minDate = getDate(data[0]),
    maxDate = getDate(data[data.length-1]);

var x = d3.time.scale().domain([minDate, maxDate]).range([0, w]);

那么你就不需要处理时间间隔函数了，你可以给x一个日期:

.attr("d", d3.svg.line()
    .x(function(d) { return x(getDate(d)) })
    .y(function(d) { return y(d.jsonHitCount) })
);

在这里工作:http://jsfiddle.net/nrabinowitz/JTrnC/