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java - 尝试使用 Spring Boot REST 从 POST 读取 JSON 字符串

转载 作者:IT老高 更新时间:2023-10-28 12:44:21 25 4
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我正在使用最新版本的 Spring Boot 通过 Restful Web Service 读取示例 JSON...

这是我的 pom.xml:

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0
http://maven.apache.org/maven-v4_0_0.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

<modelVersion>4.0.0</modelVersion>

<groupId>org.springframework</groupId>
<artifactId>myservice</artifactId>
<version>0.1.0</version>

<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>1.2.2.RELEASE</version>
</parent>

<properties>
<java.version>1.7</java.version>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding>
</properties>

<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-test</artifactId>
<scope>test</scope>
</dependency>
<dependency>
<groupId>org.springframework.data</groupId>
<artifactId>spring-data-rest-webmvc</artifactId>
</dependency>
<dependency>
</dependencies>

<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
</plugin>
</plugins>
</build>

<repositories>
<repository>
<id>spring-releases</id>
<name>Spring Releases</name>
<url>https://repo.spring.io/libs-release</url>
</repository>
<repository>
<id>org.jboss.repository.releases</id>
<name>JBoss Maven Release Repository</name>
<url>https://repository.jboss.org/nexus/content/repositories/releases</url>
</repository>
</repositories>

<pluginRepositories>
<pluginRepository>
<id>spring-releases</id>
<name>Spring Releases</name>
<url>https://repo.spring.io/libs-release</url>
</pluginRepository>
</pluginRepositories>

</project>

这是我的网络服务代码:

import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.RestController;

@RestController
@RequestMapping("/myservice")
public class BaseService {

@RequestMapping(value="/process", method = RequestMethod.POST)
public void process(@RequestBody String payload) throws Exception {
System.out.println(payload);
}
}

当我使用以下命令调用它时:

curl -H "Accept: application/json" -H "Content-type: application/json" 
-X POST -d '{"name":"value"}' http://localhost:8080/myservice/process

我收到此错误消息:

{"timestamp":1427515733546,"status":400,
"error":"Bad Request",

"exception":
"org.springframework.http.converter.HttpMessageNotReadableException","
message":
"Could not read JSON: Can not deserialize instance of java.lang.String
out of START_OBJECT token\n at

[Source: java.io.PushbackInputStream@8252f; line: 1, column: 1];
nested exception is com.fasterxml.jackson.databind.JsonMappingException:
Can not deserialize instance of java.lang.String out of START_OBJECT token\n
at [Source: java.io.PushbackInputStream@8252f; line: 1, column: 1]",
"path":"/myservice/process"

我唯一想做的就是传入一些有效的 JSON(通过 curl 作为字符串)并查看 String 有效负载是否以 {"name":"value"} 的形式进入 process 方法

我可能做错了什么?

感谢您抽出宝贵时间阅读本文...

最佳答案

我认为使用 JSON 最简单/方便的方法是使用类似于 JSON 的 Java 类:https://stackoverflow.com/a/6019761

但如果您不能使用 Java 类,您可以使用这两种解决方案之一。

解决方案 1: 您可以接收 Map<String, Object>从您的 Controller :

@RequestMapping(
value = "/process",
method = RequestMethod.POST)
public void process(@RequestBody Map<String, Object> payload)
throws Exception {

System.out.println(payload);

}

使用您的请求:

curl -H "Accept: application/json" -H "Content-type: application/json" \
-X POST -d '{"name":"value"}' http://localhost:8080/myservice/process

解决方案 2: 否则您可以将 POST 有效负载作为 String :

@RequestMapping(
value = "/process",
method = RequestMethod.POST,
consumes = "text/plain")
public void process(@RequestBody String payload) throws Exception {

System.out.println(payload);

}

然后根据需要解析字符串。注意必须指定consumes = "text/plain"在您的 Controller 上。在这种情况下,您必须使用 Content-type: text/plain 更改您的请求。 :

curl -H "Accept: application/json" -H "Content-type: text/plain" -X POST \
-d '{"name":"value"}' http://localhost:8080/myservice/process

关于java - 尝试使用 Spring Boot REST 从 POST 读取 JSON 字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29313687/

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