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python - 检查键是否存在并使用 Python 迭代 JSON 数组

转载 作者:IT老高 更新时间:2023-10-28 12:42:14 30 4
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我有一堆来自 Facebook 帖子的 JSON 数据,如下所示:

{"from": {"id": "8", "name": "Mary Pinter"}, "message": "How ARE you?", "comments": {"count": 0}, "updated_time": "2012-05-01", "created_time": "2012-05-01", "to": {"data": [{"id": "1543", "name": "Honey Pinter"}]}, "type": "status", "id": "id_7"}

JSON 数据是半结构化的,而且都不相同。以下是我的代码:

import json 

str = '{"from": {"id": "8", "name": "Mary Pinter"}, "message": "How ARE you?", "comments": {"count": 0}, "updated_time": "2012-05-01", "created_time": "2012-05-01", "to": {"data": [{"id": "1543", "name": "Honey Pinter"}]}, "type": "status", "id": "id_7"}'
data = json.loads(str)

post_id = data['id']
post_type = data['type']
print(post_id)
print(post_type)

created_time = data['created_time']
updated_time = data['updated_time']
print(created_time)
print(updated_time)

if data.get('application'):
app_id = data['application'].get('id', 0)
print(app_id)
else:
print('null')

#if data.get('to'):
#... This is the part I am not sure how to do
# Since it is in the form "to": {"data":[{"id":...}]}

我希望代码将 to_id 打印为 1543 else print 'null'

我不知道该怎么做。

最佳答案

import json

jsonData = """{"from": {"id": "8", "name": "Mary Pinter"}, "message": "How ARE you?", "comments": {"count": 0}, "updated_time": "2012-05-01", "created_time": "2012-05-01", "to": {"data": [{"id": "1543", "name": "Honey Pinter"}]}, "type": "status", "id": "id_7"}"""

def getTargetIds(jsonData):
data = json.loads(jsonData)
if 'to' not in data:
raise ValueError("No target in given data")
if 'data' not in data['to']:
raise ValueError("No data for target")

for dest in data['to']['data']:
if 'id' not in dest:
continue
targetId = dest['id']
print("to_id:", targetId)

输出:

In [9]: getTargetIds(s)
to_id: 1543

关于python - 检查键是否存在并使用 Python 迭代 JSON 数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24898797/

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