c++ - 命名空间中的主要内容

Question

为什么不编译？链接器找不到main，但是为什么会这样呢？

namespace somenamespace{

int main(void){
 return 0;
}

}

Answer 1

3.6.1/1 - "A program shall contain a global function called main, which is the designated start of the program. It is implementation-defined whether a program in a freestanding environment is required to define a main function. [ Note: in a freestanding environment, start-up and termination is implementation-defined; startup contains the execution of constructors for objects of namespace scope with static storage duration; termination contains the execution of destructors for objects with static storage duration. —end note ]

您的示例将“main”(用作程序入口点)作为命名空间函数，因此您的代码格式错误。这并不意味着不能像您那样定义函数“main”。这只是意味着 独立程序需要根据标准定义的签名对“main”进行全局命名空间范围定义。 托管程序