- mongodb - 在 MongoDB mapreduce 中,如何展平值对象?
- javascript - 对象传播与 Object.assign
- html - 输入类型 ="submit"Vs 按钮标签它们可以互换吗?
- sql - 使用 MongoDB 而不是 MS SQL Server 的优缺点
升级 flutter run 后,应用无法运行。我升级是因为 ImageStreamListener
我试图改变不同的 channel [master, stable, dev] 并且不起作用。
我找到了 this Flutter 中的问题,但没有帮助。
这是我的 flutter 医生
[✓] Flutter (Channel unknown, v1.7.11, on Mac OS X 10.14.5 18F132, locale en-PE)
[✓] Android toolchain - develop for Android devices (Android SDK version 28.0.3)
[✓] Xcode - develop for iOS and macOS (Xcode 10.2.1)
[✓] iOS tools - develop for iOS devices
[✓] Chrome - develop for the web
[✓] Android Studio (version 3.4)
[!] IntelliJ IDEA Ultimate Edition (version 2019.1)
✗ Flutter plugin not installed; this adds Flutter specific functionality.
✗ Dart plugin not installed; this adds Dart specific functionality.
[✓] VS Code (version 1.36.0)
[✓] Connected device (3 available)
还有错误提示
Compiler message:
file:///Users/enzoftware/Development/flutter/.pub-cache/hosted/pub.dartlang.org/palette_generator-0.1.1/lib/palette_generator.dart:188:29: Error: The argument type 'void Function(ImageInfo, bool)' can't be assigned to the parameter type 'ImageStreamListener'.
- 'ImageInfo' is from 'package:flutter/src/painting/image_stream.dart' ('file:///Users/enzoftware/Development/flutter/packages/flutter/lib/src/painting/image_stream.dart').
- 'ImageStreamListener' is from 'package:flutter/src/painting/image_stream.dart' ('file:///Users/enzoftware/Development/flutter/packages/flutter/lib/src/painting/image_stream.dart').
Try changing the type of the parameter, or casting the argument to 'ImageStreamListener'.
stream.removeListener(imageListener);
^
file:///Users/enzoftware/Development/flutter/.pub-cache/hosted/pub.dartlang.org/palette_generator-0.1.1/lib/palette_generator.dart:194:31: Error: The argument type 'void Function(ImageInfo, bool)' can't be assigned to the parameter type 'ImageStreamListener'.
- 'ImageInfo' is from 'package:flutter/src/painting/image_stream.dart' ('file:///Users/enzoftware/Development/flutter/packages/flutter/lib/src/painting/image_stream.dart').
- 'ImageStreamListener' is from 'package:flutter/src/painting/image_stream.dart' ('file:///Users/enzoftware/Development/flutter/packages/flutter/lib/src/painting/image_stream.dart').
Try changing the type of the parameter, or casting the argument to 'ImageStreamListener'.
stream.removeListener(imageListener);
^
file:///Users/enzoftware/Development/flutter/.pub-cache/hosted/pub.dartlang.org/palette_generator-0.1.1/lib/palette_generator.dart:201:24: Error: The argument type 'void Function(ImageInfo, bool)' can't be assigned to the parameter type 'ImageStreamListener'.
- 'ImageInfo' is from 'package:flutter/src/painting/image_stream.dart' ('file:///Users/enzoftware/Development/flutter/packages/flutter/lib/src/painting/image_stream.dart').
- 'ImageStreamListener' is from 'package:flutter/src/painting/image_stream.dart' ('file:///Users/enzoftware/Development/flutter/packages/flutter/lib/src/painting/image_stream.dart').
Try changing the type of the parameter, or casting the argument to 'ImageStreamListener'.
stream.addListener(imageListener);
^
Compiler failed on /Users/enzoftware/Projects/Wibo/wibo-flutter-mobile-user/lib/main.dart
FAILURE: Build failed with an exception.
* Where:
Script '/Users/enzoftware/Development/flutter/packages/flutter_tools/gradle/flutter.gradle' line: 652
* What went wrong:
Execution failed for task ':app:compileflutterBuildDebugArm'.
> Process 'command '/Users/enzoftware/Development/flutter/bin/flutter'' finished with non-zero exit value 1
* Try:
Run with --stacktrace option to get the stack trace. Run with --info or --debug option to get more log output. Run with --scan to get full insights.
* Get more help at https://help.gradle.org
BUILD FAILED in 29s
Running Gradle task 'assembleDebug'...
Running Gradle task 'assembleDebug'... Done 29.7s
Gradle task assembleDebug failed with exit code 1
提前致谢。
最佳答案
该 API 最近发生了重大变化。
这是一个新旧用法的例子
// get the width, height
Image image = new Image.file(myImageFile);
Completer<ImageInfo> completer = Completer();
// Old API
// image.image
// .resolve(new ImageConfiguration())
// .addListener((ImageInfo info, bool _) {
// completer.complete(info);
// });
// New API
image.image
.resolve(new ImageConfiguration())
.addListener(ImageStreamListener((ImageInfo info, bool _) {
completer.complete(info);
}));
// wait for ImageInfo to finish
ImageInfo imageInfo = await completer.future;
关于android - 错误 : The argument type 'void Function(ImageInfo, bool)' can't be assigned to the parameter type 'ImageStreamListener' ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56957461/
main.cpp #include "Primes.h" #include int main(){ std::string choose; int num1, num2; w
似乎函数 qwertyInches() 应该可以工作但是当我在 main() 中调用它时它给了我 [Error] called object 'qwertyInches' is not a funct
我无法理解 C++ 语法的工作原理。 #include using namespace std; class Accumulator{ private: int value; public:
在 类中声明 函数成员时,我们可以同时执行这两种操作; Function first; Function() second; 它们之间有什么区别? 最佳答案 Function 代表任意函数: void
“colonna”怎么可能是一个简单的字符串: $('td.' + colonna).css('background-color','#ffddaa'); 可以正确突出显示有趣单元格的背景,并且: $
我正在尝试将网页中的动态参数中继到函数中,然后函数将它们传递给函数内部的调用。比如下面这个简化的代码片段,现在这样,直接传入参数是没有问题的。但是,如何在不为每个可能的 colorbox 参数设置 s
C++ 中是否有一种模式允许您返回一个函数,它返回一个函数本身。例如 std::function func = ...; do { func = func(); } while (func);
我正在将 Windows 程序集移植到 Linux。我有一些代码要移植。我实际上是 linux 中 C 的新手。我知道 C 基础知识是一样的! typedef struct sReader {
我一直在寻找一个很好的解释,所以我很清楚。示例: this.onDeleteHandler(index)}/> 对比 对比 this.nameChangedhandler(event, perso
function(){}.__proto__ === Function.prototype 和 Function.prototype === function(){}.__proto__ 得到不同的结
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Function 据说 Propert
VBA 中的函数没有特殊类型。我很难理解如何在 Excel VBA 中将函数作为参数添加到函数中。 我想要完成的是这样的事情: function f(g as function, x as strin
所以我正在尝试制作一个包(我没有在下面包含我的 roxygen2 header ): 我有这个功能: date_from_text % dplyr::mutate(!!name := lubr
尝试从 std::function 派生一个类,对于初学者来说,继承构造函数。这是我的猜测: #include #include using namespace std; template cla
我正在尝试编写一个返回另一个函数的函数。我的目标是编写一个函数,它接受一个对象并返回另一个函数“search”。当我使用键调用搜索函数时,我想从第一个函数中给定的对象返回该键的值。 propertyO
我非常清楚函数式编程技术和命令式编程技术之间的区别。但是现在有一种普遍的趋势是谈论“函数式语言”,这确实让我感到困惑。 当然,像 Haskell 这样的一些语言比 C 等其他语言更欢迎函数式编程。但即
关闭。这个问题是opinion-based 。目前不接受答案。 想要改进这个问题吗?更新问题,以便 editing this post 可以用事实和引文来回答它。 . 已关闭 8 年前。 Improv
我在stackoverflow上查过很多类似的问题,比如call.call 1 , call.call 2 ,但我是新人,无法发表任何评论。我希望我能找到关于 JavaScript 解释器如何执行这些
向 Twilio 发送 SMS 时,Twilio 会向指定的 URL 发送多个请求,以通过 Webhook 提供该 SMS 传送的状态。我想让这个回调异步,所以我开发了一个 Cloud Functio
作为 IaC 的一部分,A 功能应用 ,让我们将其命名为 FuncAppX 是使用 Terraform 部署的,它有一个内置函数。 我需要使用 Terraform 在函数应用程序中访问相同函数的 Ur
我是一名优秀的程序员,十分优秀!