c++ - "error : a nonstatic member reference must be relative to a specific object"是什么意思？

Question

int CPMSifDlg::EncodeAndSend(char *firstName, char *lastName, char *roomNumber, char *userId, char *userFirstName, char *userLastName)
{
    ...

    return 1;
}

extern "C"
{
    __declspec(dllexport) int start(char *firstName, char *lastName, char *roomNumber, char *userId, char *userFirstName, char *userLastName)
    {
        return CPMSifDlg::EncodeAndSend(firstName, lastName, roomNumber, userId, userFirstName, userLastName);
    }
}

在线 return CPMSifDlg::EncodeAndSend 我有一个错误:错误:非静态成员引用必须相对于特定对象。

什么意思？

Answer 1

EncodeAndSend 不是静态函数，这意味着它可以在 CPMSifDlg 类的实例上调用。你不能这样写:

 CPMSifDlg::EncodeAndSend(/*...*/);  //wrong - EncodeAndSend is not static

它应该被称为:

 CPMSifDlg dlg; //create instance, assuming it has default constructor!
 dlg.EncodeAndSend(/*...*/);   //correct