Flutter ListTile 启用多选 onLongPress

Question

我想在 Google Keep 中实现类似的功能。

如何在长按时启用多项选择并更改标题按钮，以便稍后删除这些选定的项目？

我当前的 Dart 代码:

@override
  Widget build(BuildContext context) {
    return new Card(
      child: new Column(mainAxisSize: MainAxisSize.min, children: <Widget>[
        new ListTile(
          leading: const Icon(Icons.info),
          title: new Text(item.name),
          subtitle: new Text(item.description),
          trailing: new Text(item.dateTime.month.toString()),
          onTap: () => _openEditDialog(context, item),
          onLongPress: // what should I put here,
        )
      ]),
    );
  }

Answer 1

当用户长按ListTile必须将所选属性更改为 true，反之亦然，并且卡片颜色必须更改为类似于 Grey[300] 的内容

class cardy extends StatefulWidget {
  @override
  _cardyState createState() => new _cardyState();
}

class _cardyState extends State<cardy> {
  var isSelected = false;
  var mycolor=Colors.white;

  @override
  Widget build(BuildContext context) {
    return new Card(
      color: mycolor,
      child: new Column(mainAxisSize: MainAxisSize.min, children: <Widget>[
        new ListTile(
            selected: isSelected,
            leading: const Icon(Icons.info),
            title: new Text("Test"),
            subtitle: new Text("Test Desc"),
            trailing: new Text("3"),
            onLongPress: toggleSelection // what should I put here,
            )
      ]),
    );
  }

  void toggleSelection() {
    setState(() {
      if (isSelected) {
        mycolor=Colors.white;
        isSelected = false;
      } else {
        mycolor=Colors.grey[300];
        isSelected = true;
      }
    });
  }
}

编辑:如果要获得边框着色效果，请在容器内制作列并将装饰属性设置为变量并调用它 border 并编辑选择方法

void toggleSelection() {
    setState(() {
      if (isSelected) {
        border=new BoxDecoration(border: new Border.all(color: Colors.white));
        mycolor = Colors.white;
        isSelected = false;
      } else {
        border=new BoxDecoration(border: new Border.all(color: Colors.grey));
        mycolor = Colors.grey[300];
        isSelected = true;
      }
    });
  }