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spring - 如何从 spring-data mongodb 扩展 SimpleMongoRepository?

转载 作者:IT老高 更新时间:2023-10-28 12:30:59 27 4
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我正在尝试创建一个可以被所有 DAO 扩展的 BaseDAO 接口(interface)。该项目使用带有 mongodb 的 spring-data。问题是,如果我让所有单独的 DAO 扩展 MongoRepository 并且不编写实现类,那么一切正常。但是,如果我尝试使用泛型将 MongoRepository 添加到 BaseDAO 接口(interface),该应用程序将不再工作,因为实例化 SimpleMongoRepository 所需的参数为空。这是我到目前为止的代码:

BaseDAO.java

import com.test.mongodb.BaseEntity;
import org.springframework.data.mongodb.repository.MongoRepository;
import org.springframework.data.repository.NoRepositoryBean;

import java.io.Serializable;

@NoRepositoryBean
public interface BaseDAO<T extends BaseEntity, ID extends Serializable> extends MongoRepository<T, ID> {
public T getTestObject(ID id);
}

BaseDAOImpl.java

import com.test.mongodb.BaseEntity;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.data.mongodb.core.MongoTemplate;
import org.springframework.data.mongodb.repository.query.EntityInformationCreator;
import org.springframework.data.mongodb.repository.query.MongoEntityInformation;
import org.springframework.data.mongodb.repository.support.SimpleMongoRepository;
import org.springframework.data.repository.NoRepositoryBean;

import java.io.Serializable;

@NoRepositoryBean
public class BaseDAOImpl<T extends BaseEntity, ID extends Serializable> extends SimpleMongoRepository<T,
ID> implements BaseDAO<T, ID> {

@Autowired
private static MongoTemplate mongoTemplate;

@Autowired
private static EntityInformationCreator entityInformationCreator;

public BaseDAOImpl(Class<T> type){
super((MongoEntityInformation<T, ID>) entityInformationCreator.getEntityInformation(type), mongoTemplate);
}

@Override
public T getTestObject(ID id){
return findOne(id);
}
}

UserDAO.java

import com.test.mongodb.User;
import org.springframework.stereotype.Repository;

@Repository
public interface UserDAO extends BaseDAO<User, String> {}

UserDAOImpl.java

import com.test.mongodb.User;
import org.springframework.stereotype.Repository;

@Repository
public class UserDAOImpl extends BaseDAOImpl<User, String> implements UserDAO {

public UserDAOImpl(){
super(User.class);
}
}

applicationContext.xml

    <?xml version="1.0" encoding="UTF-8"?><beans xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.springframework.org/schema/beans"
xmlns:mongo="http://www.springframework.org/schema/data/mongo"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/data/mongo http://www.springframework.org/schema/data/mongo/spring-mongo-1.1.xsd">

<!-- MongoFactoryBean instance -->
<mongo:mongo host="localhost" port="27017" />

<mongo:db-factory dbname="bank" mongo-ref="mongo" />

<!-- MongoTemplate instance -->
<bean id="mongoTemplate" class="org.springframework.data.mongodb.core.MongoTemplate">
<constructor-arg name="mongoDbFactory" ref="mongoDbFactory" />
</bean>

<bean id="mappingContext" class="org.springframework.data.mongodb.core.mapping.MongoMappingContext" />

<bean id="entityInformationCreator" class="org.springframework.data.mongodb.repository.support.DefaultEntityInformationCreator">
<constructor-arg name="mappingContext" ref="mappingContext" />
</bean>
<mongo:repositories base-package="com.test.mongodb.repo"/>
</beans>

App.java

public class App {

public static void main(String[] args) {
ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");

UserRepository userRepository = context.getBean("userRepository", UserRepository.class);

User user = new User("Test User");

userRepository.save(user);

String id = user.getId();
System.out.println(id);

System.out.println(userRepository.getTestObject(user.getId()));
}
}

所以当我运行它时,我在 BaseDAOImpl 中得到一个 NPE,因为 mongoTemplate 和 entityInformationCreator 都是空的。我如何加载它们?我还查看了 Spring MongoDB 引用文档,但它主要说要遵循其他类型存储库的文档。我在网上和其他地方唯一能找到的就是创建一个工厂 bean。所以我也尝试了:

MongoRepoFactoryBean.java

import org.springframework.data.mongodb.core.MongoTemplate;
import org.springframework.data.mongodb.repository.MongoRepository;
import org.springframework.data.mongodb.repository.support.MongoRepositoryFactory;
import org.springframework.data.mongodb.repository.support.MongoRepositoryFactoryBean;
import org.springframework.data.repository.NoRepositoryBean;
import org.springframework.data.repository.core.support.RepositoryFactorySupport;

import java.io.Serializable;

@NoRepositoryBean
public class MongoRepoFactoryBean<T extends MongoRepository<?,?>, ID extends
Serializable> extends MongoRepositoryFactoryBean {

protected RepositoryFactorySupport createRepositoryFactory(Class<T> clazz, MongoTemplate mongoTemplate) {
return new MongoRepoFactory(clazz, mongoTemplate);
}

private static class MongoRepoFactory extends MongoRepositoryFactory {
private Class clazz;
private MongoTemplate mongoTemplate;

public MongoRepoFactory(Class clazz, MongoTemplate mongoTemplate) {
super(mongoTemplate);
this.mongoTemplate = mongoTemplate;
this.clazz = clazz;
}

public Object getTargetRepository() {
return new BaseDAOImpl(clazz);
}

public Class<?> getRepositoryBaseClass() {
return BaseDAOImpl.class;
}
}
}

并将 applicationContext.xml 更改为:

<mongo:repositories base-package="com.test.mongodb.repo"
factory-class="com.test.mongodb.repo.MongoRepoFactoryBean"/>

但这也不起作用。我也尝试过使用 JavaConfig,但是在使用注释进行配置时,我不知道如何设置工厂类。我究竟做错了什么? SimpleMongoRepository 没有默认构造函数。注入(inject)静态字段有问题吗?

最佳答案

引用文档已过时,未反射(reflect) spring-data-mongodb 1.1.1.RELEASE 的更改。

我和你有同样的问题,这是我的解决方法。

请注意,我同时使用了 MongoConfig 类和应用上下文 XML,但你真的不需要两者,我只是决定这样做以举例说明它们的用法。

MongoConfig 类:(你也可以通过 spring 应用上下文 XML 来实现)

@Configuration
public class MongoConfig extends AbstractMongoConfiguration {
@Override
protected String getDatabaseName() {
return "myDb";
}

@Override
@Bean
public Mongo mongo() throws Exception {
return new Mongo("localhost");
}
}

Spring 应用上下文 XML:

<!-- You can also expose the bean as a method in the MongoConfig class -->
<bean id="mongoRepositoryFactory" class="org.springframework.data.mongodb.repository.support.MongoRepositoryFactory">
<!-- mongoTemplate comes from AbstractMongoConfiguration -->
<constructor-arg ref="mongoTemplate" />
</bean>

<context:annotation-config />
<context:component-scan base-package="com.example.domain" />
<mongo:repositories base-package="com.example.domain.repository" mongo-template-ref="mongoTemplate" />

我的存储库/dao 类:

@Repository
public class MyBeanDao extends SimpleMongoRepository<MyBean, String> {

public MyBeanDao(MongoEntityInformation<MyBean, String> metadata, MongoOperations mongoOperations) {
super(metadata, mongoOperations);
}

@Autowired
public MyBeanDao(MongoRepositoryFactory factory, MongoOperations mongoOperations) {
this(factory.<MyBean, String>getEntityInformation(MyBean.class), mongoOperations);
}

... // more stuff
}

我知道这真的很难看,并且只适用于 Java 6,但由于 getEntityInformation() 的返回类型是完全无界的,要么就是 ID 类型是 Serializable 而不是你的实际 ID 类型,然后进行显式转换每次你需要它。

我希望有一种更简洁的方法,但我已经通过 API 甚至源代码查看了相当长的时间,并且没有找到更好的方法来做到这一点,而无需自己实现一些spring-data-mongodb 类。

希望对你有帮助。

关于spring - 如何从 spring-data mongodb 扩展 SimpleMongoRepository?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14344809/

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