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我是 iPhone 新手。谁能告诉我解析这些数据并获取事件详细信息、名字和姓氏的步骤?
{
"#error": false,
"#data": {
"": {
"activity_id": "35336",
"user_id": "1",
"user_first_name": "Chandra Bhusan",
"user_last_name": "Pandey",
"time": "1300870420",
"activity_details": "Good\n",
"activity_type": "status_update",
"photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/sites/default/files/pictures/picture-1627435117.jpg"
},
"boolean": "1",
"1": {
"1": {
"photo_1_id": "9755"
},
"activity_id": "35294",
"album_name": "Kalai_new_Gallery",
"user_id": "31",
"album_id": "9754",
"user_first_name": "Kalaiyarasan",
"user_last_name": "Balu",
"0": {
"photo_0_id": "9756"
},
"time": "1300365758",
"activity_type": "photo_upload",
"photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/"
},
"3": {
"activity_id": "35289",
"user_id": "33",
"user_first_name": "Girija",
"user_last_name": "S",
"time": "1300279636",
"activity_details": "girija Again\n",
"activity_type": "status_update",
"photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/sites/default/files/pictures/picture-33-6361851323080768.jpg"
},
"2": {
"owner_first_name": "Girija",
"activity_id": "35290",
"activity_details": "a:2:{s:4:\"html\";s:51:\"!user_fullname and !friend_fullname are now friends\";s:4:\"type\";s:10:\"friend_add\";}",
"activity_type": "friend accept",
"owner_last_name": "S",
"time": "1300280400",
"photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/sites/default/files/pictures/picture-33-6361851323080768.jpg",
"owner_id": "33"
},
"4": {
"activity_id": "35288",
"user_id": "33",
"user_first_name": "Girija",
"user_last_name": "S",
"time": "1300279530",
"activity_details": "girija from mobile\n",
"activity_type": "status_update",
"photo_url": "http://184.73.155.44/hcl-meme/QA_TEST/sites/default/files/pictures/picture-33-6361851323080768.jpg"
}
}
}
最佳答案
从 OS X v10.7 和 iOS 5 发布的角度来看,现在最先推荐的可能是 NSJSONSerialization
, Apple 提供的 JSON 解析器。如果您发现该类在运行时不可用,请仅将第三方选项用作备用选项。
所以,例如:
NSData *returnedData = ...JSON data, probably from a web request...
// probably check here that returnedData isn't nil; attempting
// NSJSONSerialization with nil data raises an exception, and who
// knows how your third-party library intends to react?
if(NSClassFromString(@"NSJSONSerialization"))
{
NSError *error = nil;
id object = [NSJSONSerialization
JSONObjectWithData:returnedData
options:0
error:&error];
if(error) { /* JSON was malformed, act appropriately here */ }
// the originating poster wants to deal with dictionaries;
// assuming you do too then something like this is the first
// validation step:
if([object isKindOfClass:[NSDictionary class]])
{
NSDictionary *results = object;
/* proceed with results as you like; the assignment to
an explicit NSDictionary * is artificial step to get
compile-time checking from here on down (and better autocompletion
when editing). You could have just made object an NSDictionary *
in the first place but stylistically you might prefer to keep
the question of type open until it's confirmed */
}
else
{
/* there's no guarantee that the outermost object in a JSON
packet will be a dictionary; if we get here then it wasn't,
so 'object' shouldn't be treated as an NSDictionary; probably
you need to report a suitable error condition */
}
}
else
{
// the user is using iOS 4; we'll need to use a third-party solution.
// If you don't intend to support iOS 4 then get rid of this entire
// conditional and just jump straight to
// NSError *error = nil;
// [NSJSONSerialization JSONObjectWithData:...
}
关于objective-c - 如何使用 Objective-C 解析 JSON?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5547311/
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