PHP类型提示原始值？

Question

我想知道是否可以对一种方法进行类型提示以期望原始类型？

类似这样的:

public function someMethod(string $str)
                         //^^^^^^

或者:

private function anotherMethod(int $num)
                             //^^^

和你一样:

private function otherMethod(Person $rambo)
                           //^^^^^^

在 php 中可以吗？

Answer 1

在 PHP 7 中，他们添加了以下内容:

Type declarations allow functions to require that parameters are of a certain type at call time. If the given value is of the incorrect type, then an error is generated: in PHP 5, this will be a recoverable fatal error, while PHP 7 will throw a TypeError exception.

引用: http://php.net/manual/en/functions.arguments.php#functions.arguments.type-declaration

---

当被问及这个答案时，PHP 5 是最新的，并说如下:

PHP 5 introduces type hinting. Functions are now able to force parameters to be objects (by specifying the name of the class in the function prototype), interfaces, arrays (since PHP 5.1) or callable (since PHP 5.4). However, if NULL is used as the default parameter value, it will be allowed as an argument for any later call.

If class or interface is specified as type hint then all its children or implementations are allowed too.

Type hints cannot be used with scalar types such as int or string. Resources and Traits are not allowed either.

引用:http://php.net/manual/en/language.oop5.typehinting.php