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java - org.hibernate.MappingException : Could not determine type for: java. util.List,在表 : College, 的列 : [org. hibernate.mapping.Column(students)]

转载 作者:IT老高 更新时间:2023-10-28 11:44:12 29 4
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我将 Hibernate 用于我项目中的所有 CRUD 操作。它不适用于一对多和多对一关系。它给了我以下错误。

org.hibernate.MappingException:无法确定类型:java.util.List,表:College,列:[org.hibernate.mapping.Column(students)]

然后我又经历了video tutorial .一开始对我来说很简单。但是,我不能让它工作。现在也是,说

org.hibernate.MappingException:无法确定类型:java.util.List,表:College,列:[org.hibernate.mapping.Column(students)]

我在互联网上进行了一些搜索,有人告诉 its a bug in Hibernate ,有人说,通过添加 @GenereatedValue这个错误会被清除,但它对我不起作用。

College.java

@Entity
public class College {
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private int collegeId;
private String collegeName;


private List<Student> students;

@OneToMany(targetEntity=Student.class, mappedBy="college", fetch=FetchType.EAGER)
public List<Student> getStudents() {
return students;
}
public void setStudents(List<Student> students) {
this.students = students;
}//Other gettters & setters omitted

Student.java

@Entity
public class Student {


@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private int studentId;
private String studentName;


private College college;

@ManyToOne
@JoinColumn(name="collegeId")
public College getCollege() {
return college;
}
public void setCollege(College college) {
this.college = college;
}//Other gettters & setters omitted

Main.java:

public class Main {

private static org.hibernate.SessionFactory sessionFactory;

public static SessionFactory getSessionFactory() {
if (sessionFactory == null) {
initSessionFactory();
}
return sessionFactory;
}

private static synchronized void initSessionFactory() {
sessionFactory = new AnnotationConfiguration().configure().buildSessionFactory();

}

public static Session getSession() {
return getSessionFactory().openSession();
}

public static void main (String[] args) {
Session session = getSession();
Transaction transaction = session.beginTransaction();
College college = new College();
college.setCollegeName("Dr.MCET");

Student student1 = new Student();
student1.setStudentName("Peter");

Student student2 = new Student();
student2.setStudentName("John");

student1.setCollege(college);
student2.setCollege(college);



session.save(student1);
session.save(student2);
transaction.commit();
}


}

控制台:

 Exception in thread "main" org.hibernate.MappingException: Could not determine type  for: java.util.List, at table: College, for columns:  [org.hibernate.mapping.Column(students)]
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:306)
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:290)
at org.hibernate.mapping.Property.isValid(Property.java:217)
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:463)
at org.hibernate.mapping.RootClass.validate(RootClass.java:235)
at org.hibernate.cfg.Configuration.validate(Configuration.java:1330)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1833)
at test.hibernate.Main.initSessionFactory(Main.java:22)
at test.hibernate.Main.getSessionFactory(Main.java:16)
at test.hibernate.Main.getSession(Main.java:27)
at test.hibernate.Main.main(Main.java:43)

XML:

<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<!-- Database connection settings -->
<property name="connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="connection.url">jdbc:mysql://localhost:3306/dummy</property>
<property name="connection.username">root</property>
<property name="connection.password">1234</property>
<!-- JDBC connection pool (use the built-in) -->
<property name="connection.pool_size">1</property>
<!-- SQL dialect -->
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<!-- Enable Hibernate's automatic session context management -->
<property name="current_session_context_class">thread</property>
<!-- Disable the second-level cache -->
<property name="cache.provider_class">org.hibernate.cache.NoCacheProvider</property>
<!-- Echo all executed SQL to stdout -->
<property name="show_sql">true</property>
<!-- Drop and re-create the database schema on startup -->
<property name="hbm2ddl.auto">update</property>

<mapping class="test.hibernate.Student" />
<mapping class="test.hibernate.College" />
</session-factory>

最佳答案

您正在使用字段访问策略(由@Id 注解确定)。将任何与 JPA 相关的注释放在每个字段的正上方,而不是 getter 属性

@OneToMany(targetEntity=Student.class, mappedBy="college", fetch=FetchType.EAGER)
private List<Student> students;

关于java - org.hibernate.MappingException : Could not determine type for: java. util.List,在表 : College, 的列 : [org. hibernate.mapping.Column(students)],我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3774198/

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