iphone - 测试应用程序是否确实从 UILocalNotification 变为事件状态

Question

有没有办法通过本地通知知道应用程序是否已激活？

我知道有一种方法可以测试应用程序是否从本地通知警报启动；但如果它只是坐在后台并收到通知？

当应用激活时，我需要运行不同的代码:

1. 来自本地通知。
2. 刚刚开始活跃:)

有办法吗？

Answer 1

我从@naveed 关于在调用 didReceiveNotification 方法时检查应用程序状态的提示中得到了解决方案的线索。当应用从后台恢复时，无需检查变量等。

在 iOS7 及更低版本上，您可以这样处理通知:

- (void)application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)notification {
    if (application.applicationState == UIApplicationStateInactive ) {
         //The application received the notification from an inactive state, i.e. the user tapped the "View" button for the alert.
         //If the visible view controller in your view controller stack isn't the one you need then show the right one.
    }

    if(application.applicationState == UIApplicationStateActive ) { 
        //The application received a notification in the active state, so you can display an alert view or do something appropriate.
    }
}

iOS 8 更新:现在通过通知从后台打开应用程序时会调用以下方法。

- (void)application:(UIApplication *)application handleActionWithIdentifier:(NSString *)identifier forLocalNotification:(UILocalNotification *)notification completionHandler:(void(^)())completionHandler {
}

- (void)application:(UIApplication *)application handleActionWithIdentifier:(NSString *)identifier forRemoteNotification:(NSDictionary *)userInfo completionHandler:(void(^)())completionHandler {
}

如果在应用处于前台时收到通知，请使用以下方法:

- (void) application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *) userInfo {
}

- (void) application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)notification {
}

请注意，除非您想在应用中支持旧版本的操作系统，否则无需检查应用状态。