gpt4 book ai didi

Model.findByIdAndRemove() no longer accepts a callback(Model.findByIdAndRemove()不再接受回调)

转载 作者:bug小助手 更新时间:2023-10-28 22:35:27 24 4
gpt4 key购买 nike



When I check the checkbox on my to do list I get an error that say "Model.findByIdAndRemove() no longer accepts a callback".

当我选中待办事项列表上的复选框时,我收到一个错误,显示“Model.findByIdAndRemove()不再接受回调”。


I am trying to make it so that when an item is checked it is removed from my to do list.

我正在尝试这样做,这样当一项被选中时,它就会从我的待办事项列表中删除。


app.post("/delete", function (req, res) {
const checkedItemId = req.body.checkbox;
Item.findByIdAndRemove(checkedItemId, function (err) {
if (!err) {
console.log("Successfully deleted checked item");
res.redirect("/");
}
});
});

更多回答
优秀答案推荐

This can be easily rolsolved by using async/await pattern, and findByIdAndDelete method like so:

这可以通过使用异步/等待模式和findByIdAndDelete方法轻松解决,如下所示:


app.post("/delete", async (req, res) => { //< Note the use of async and arrow function
try { //< Use a try/catch block for cleaner error handling
const checkedItemId = req.body.checkbox;
const deletedItem = await Item.findByIdAndDelete(checkedItemId); //< Note the use of await keyword
console.log("Successfully deleted checked item:", deletedItem);
res.redirect("/");
} catch(err){
console.log('Error:', err);
//Send error message to front-end
}
});

The findByIdAndDelete method fires the findOneAndDelete middleware, which has a useful number of options. See here for the docs.

FindByIdAndDelete方法触发findOneAndDelete中间件,该中间件具有许多有用的选项。请看这里的文档。


更多回答

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com