I have a simple struct Parser

我有一个简单的结构解析器

pub struct Parser {
    pos: usize,
    input: String,
}

I'm trying to build a markdown parser and there's a method parse_md_line which contains a while loop and I'm trying to make the while loop's condition dynamic based on delimiter value

我正在尝试构建一个markdown解析器，并且有一个包含While循环的方法parse_md_line，并且我正在尝试根据分隔符值动态设置While循环的条件

pub fn parse_md_line(&mut self, delimiter: Option<char>) -> String {
    let mut result = String::new();

    let mut cond: Box<dyn Fn() -> bool> = Box::new(|| {
        return self.pos < self.input.len()
            && (self.next_char() != '\n' || utils::is_whitespace(self.next_char()));
    });

    if delimiter.is_some() {
        cond = Box::new(|| {
            return self.pos < self.input.len() && self.next_char() != delimiter.unwrap();
        });
    }

    while cond() {
        let normal_text = self.parse_alpha_numeric(true); // this mutates `self`
        .....
    }
 
  result
 }

while loop's inner working are hidden as they do matter much, but it calls some methods, which mutates self.

虽然循环的内部工作是隐藏的，因为它们确实很重要，但它调用了一些方法，这会使自身发生突变。

This code throw error for let normal_text = self.parse_alpha_numeric(true);,
**cannot borrow *self as mutable because it is also borrowed as immutable.

此代码引发错误，因为let Normal_Text=self.parse_Alpha_Numeric(True)；，**不能借用*self作为可变对象，因为它也被借用为不可变对象。

I understand the error and why it's happening. But cannot figure out a way to work it out. I hit and tried using RefCell, Rc still nothing of use.

我理解这个错误以及为什么会发生这种情况。但想不出办法来解决这个问题。我点击并尝试使用Refcell，RC仍然没有任何用处。

Maybe It can be done using RefCell, from what I've tried the code grew unnecessary complex.

也许这可以使用RefCell来完成，从我尝试的情况来看，代码变得不必要的复杂。

Is there a standard or cleaner way to handle things like this.

有没有一个标准的或更干净的方法来处理这样的事情。

Multiple issues here:

这里有多个问题：

1. Fn can't modify it's environment, you could change it to FnMut but


2. you're creating multiple closures that want to hold a mutable reference to self simultaneously but &mut self can only be held once


3. you want to modify self while the closure holds on to a exclusive reference, you can't create multiple exclusive references to self though.

To solve them you can make self a parameter for the closure, that way it doesn't need to capture self, or hold on to it across the loop body, it also doesn't need to be a FnMut because you don't modify the environment any longer:

要解决这些问题，可以将self作为闭包的参数，这样它就不需要捕获self，或者在循环体中保留它，它也不需要是FnMut，因为您不再修改环境：

pub fn parse_md_line(&mut self, delimiter: Option<char>) {
    let cond: Box<dyn Fn(&mut Self) -> bool> = if let Some(delimiter) = delimiter {
        Box::new(move |this| this.pos < this.input.len() && this.next_char() != delimiter)
    } else {
        Box::new(|this| this.pos < this.input.len() && !this.next_char().is_whitespace())
    };
    while cond(self) {
        let _normal_text = self.parse_alpha_numeric(true); // this mutates `self`
    }
}

You can also just write the condition inline to avoid any allocation of a closure and the complete problem, the compiler is clever enough to optimize the if check to ahead of the loop:

您也可以只内联编写条件，以避免任何闭包和完整问题的分配，编译器足够聪明，可以在循环之前优化if检查：

pub fn parse_md_line(&mut self, delimiter: Option<char>) {
    while self.pos < self.input.len()
        && if let Some(delimiter) = delimiter {
            self.next_char() != delimiter
        } else {
            !self.next_char().is_whitespace()
        }
    {
        let _normal_text = self.parse_alpha_numeric(true); // this mutates `self`
    }
}

Alternatively, you can avoid using methods of Self in the closure.

或者，您可以避免在闭包中使用self方法。

pub fn parse_md_line(&mut self, delimiter: Option<char>) -> String {
    let mut result = String::new();
    let mut check_delimiter: Box<dyn Fn(char) -> bool> = match delimiter {
        Some(delimiter) => Box::new(move |c| {
            c != delimiter
        }),
        None => Box::new(|c| {
            c != '\n' /* || utils::is_whitespace(self.next_char()) */
        })
    };
    while self.pos < self.input.len() && check_delimiter(self.next_char()) {
        let _normal_text = self.parse_alpha_numeric(true);
    }
    result
}

Also, with such an approach, you can avoid using the .unwrap() in the code.
playground link.

此外，使用这种方法，您可以避免在代码中使用.unwork()。操场链接。