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I have the people data below. where in people data there is "dataInduk" and inside "dataInduk" there is "dataAnak". how can I find people id data if I have "idAnak". this is my code
我有下面的数据。在人的数据中有“dataInduk”，在“dataInduk”中有“dataAnak”。如果我有“idAnak”，我怎么能找到人id数据。这是我的代码
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退出const people = [
{
name: "James",
id: 1,
dataInduk: [
{
idInduk: "1a",
dataAnak: [
{
idAnak: "1a1",
},
{
idAnak: "1a2",
},
],
},
{
idInduk: "1b",
dataAnak: [
{
idAnak: "1b1",
},
{
idAnak: "1b2",
},
],
},
],
},
{
name: "John",
id: 2,
dataInduk: [
{
idInduk: "2a",
dataAnak: [
{
idAnak: "2a1",
},
{
idAnak: "2a2",
},
],
},
{
idInduk: "2b",
dataAnak: [
{
idAnak: "2b1",
},
{
idAnak: "2b2",
},
],
},
],
},
];
for example:
when i find from idAnak = '2b2' then show id "2" from people
例如：当我找到from idAnak=‘2b2’时，则显示来自People的id“2
the data is just 3 layer deep right? Can different idInduk or people have the same idAnak?
数据只有3层深，对吗？不同的idInduk或人可以拥有相同的idAnak吗？
@kennarddh Yes, all the id are different
@kennarddh是的，所有ID都不同
@Quinn: Did any answer work for you? If yes, accept and/or upvote.
@Quinn：有什么答案对你有效吗？如果是，接受和/或赞成票。
We can find the person by iterating dataInduk and iterate dataAnak in every dataInduk to check if dataInduk includes idAnak
我们可以通过迭代dataInduk和迭代每个dataInduk中的dataAnak来找到Person，以检查dataInduk是否包括idAnak
const IDAnakToIDPeople = idAnak => {
const person = people.find(personIter =>
personIter.dataInduk.some(dataInduk =>
dataInduk.dataAnak.some(dataAnak => dataAnak.idAnak === idAnak),
),
)
return person.id
}
// Test cases (actual, expected)
console.log(IDAnakToIDPeople("1a1"), 1)
console.log(IDAnakToIDPeople("1a2"), 1)
console.log(IDAnakToIDPeople("1b1"), 1)
console.log(IDAnakToIDPeople("1b2"), 1)
console.log(IDAnakToIDPeople("2a1"), 2)
console.log(IDAnakToIDPeople("2a2"), 2)
console.log(IDAnakToIDPeople("2b1"), 2)
console.log(IDAnakToIDPeople("2b2"), 2)<script>
const people = [
{
name: "James",
id: 1,
dataInduk: [
{
idInduk: "1a",
dataAnak: [
{
idAnak: "1a1",
},
{
idAnak: "1a2",
},
],
},
{
idInduk: "1b",
dataAnak: [
{
idAnak: "1b1",
},
{
idAnak: "1b2",
},
],
},
],
},
{
name: "John",
id: 2,
dataInduk: [
{
idInduk: "2a",
dataAnak: [
{
idAnak: "2a1",
},
{
idAnak: "2a2",
},
],
},
{
idInduk: "2b",
dataAnak: [
{
idAnak: "2b1",
},
{
idAnak: "2b2",
},
],
},
],
},
];
</script>
One liner:
一条班轮：
const people=[{name:"James",id:1,dataInduk:[{idInduk:"1a",dataAnak:[{idAnak:"1a1"},{idAnak:"1a2"}]},{idInduk:"1b",dataAnak:[{idAnak:"1b1"},{idAnak:"1b2"}]}]},{name:"John",id:2,dataInduk:[{idInduk:"2a",dataAnak:[{idAnak:"2a1"},{idAnak:"2a2"}]},{idInduk:"2b",dataAnak:[{idAnak:"2b1"},{idAnak:"2b2"}]}]}];
console.log(
people.filter(e =>
e.dataInduk.some(j => j.dataAnak.some(k => k.idAnak === '2b2')))
?.map(i => i.id)
);
How is this any different from an answer already posted?
这与已经发布的答案有什么不同？
Return only 1 id because idAnak is always unique.
只返回1个id，因为idAnak始终是唯一的。
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