I am trying to combine few observables and passing the value from first one through the entire pipe.

我正在尝试组合几个可观测的变量，并将第一个变量的值传递到整个管道。

this.auth.user
      .pipe(
        switchMap((authUser) => {
          if (!authUser) {
            return of();
          }

          const docRef = doc(this.firestore, firebaseCollections.UsersCollection, authUser.uid);
          return from(getDoc(docRef));
        }),
        map((user)=>{
          if(user){
            return true;
          }
          return false
        }),
        switchMap([authUser, exists])={
          
        }
      )

On the last switchMap I would like to get the authUser from the from the first **switchMap ** but also the value from the map. I know I've done it in the past put can't find the solution anymore.

在最后一个SwitchMap上，我希望从第一个**SwitchMap**中获取authUser，同时也从map中获取值。我知道我已经做过了，现在已经找不到解决的办法了。

I guess it should be something like this but not sure witch rxjs functions should I use:

我猜应该是这样的，但不确定我应该使用哪个rxjs函数：

1: (authUser) => getFirestoreUser(authUser)

1：(AuthUser)=>getFirestore User(AuthUser)

2: (authUser, firestoreUser) => {...}

2：(authUser，FireStoreUser)=>{...}

I'm not a expertice in rxjs, but I feel you need "map" your intermediate response. Some like

我不是rxjs方面的专家，但我觉得您需要“映射”您的中间响应。有些人喜欢

this.auth.user
      .pipe(
        switchMap((authUser) => {
          if (!authUser) {
            return of([null,null] as [any,any]);
          }
          const docRef = doc(this.firestore, firebaseCollections.UsersCollection, authUser.uid);
         //see that you use here pipe(map) to return an array
          return from(getDoc(docRef)).pipe(
              map((x:any)=>[x,authUser] as [any,any])
          );
        }),
        map([user,authUser]:[any,any])=>{
          if(user){
            return [authUser,true] as [any,boolean];
          }
          return [authUser,false] as [any,boolean]
        }),
        switchMap([authUser, exists]:[any,boolean])={
          
        }
      )

NOTE: I use the "as [any:any]" to keep the type of the users

注意：我使用“as[any：any]”来保持用户的类型