I have a bot for youtube that I turn on when I stream. According to the LiveMessage documentation part of the response is how long to wait before the bot requests the list again.

我有一个YouTube机器人，当我流媒体时，它就会打开。根据LiveMessage文档，响应的一部分是机器人再次请求列表之前等待多长时间。

Usually this value is slightly over 1000. If the bot pings the server for a list of messages once every second and a list call is 5 quota(s) and I stream for an hour and a half, I would use 27000 quota. Over double the limit.

通常，该值略高于1000。如果机器人每秒向服务器ping一次消息列表，列表调用是5个配额(S)，而我流了一个半小时，我将使用27000个配额。超过了限额的两倍。

Of course, I might be polling youtube incorrectly. Here is what I am doing.

当然，我可能对YouTube进行了错误的投票。这就是我正在做的事情。

1. Send a GET request to https://www.googleapis.com/youtube/v3/liveChat/messages?liveChatId={LiveChatId}&part=id,authordetails,snippet&access_token={MyAccessToken}


2. Save pollingIntervalMillis, and nextPageToken


3. Task.Delay(MillisecondsToWait)


4. Make a GET request to https://www.googleapis.com/youtube/v3/liveChat/messages?liveChatId={LiveChatId}&part=id,authordetails,snippet&access_token={MyAccessToken}&pageToken={nextPageToken}


5. Repeat steps 2-4 until the response has the attribute offlineAt

Looking at the Java sample this approach is correct. Just, that the Java example uses a youtube object.

从Java示例来看，这种方法是正确的。Java示例使用了一个youtube对象。

How am I supposed to stay under the 10K limit if I use 5 quota points every second?

如果我每秒使用5个配额分，我怎么能保持在10K的限制之下？