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Bash: Execute git command in .bashrc failing [duplicate](Bash：在.bashrc中执行git命令失败[复制])

转载 作者：bug小助手 更新时间：2023-10-25 14:33:03 33 4
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This answer states that to find out the current branch name of a git repo, we can do

这个答案指出，要找出Git回购的当前分支名称，我们可以这样做


git rev-parse --abbrev-ref HEAD

Now, this works for me, and I want to use this command when pushing to git, i.e. I want first to find out the branch name and then push to that branch, so I wrote the following bash function into my .bashrc file:

现在，这对我有效，我想在推送到git时使用此命令，也就是说，我希望首先找到分支名称，然后推送到该分支，因此我将以下bash函数写入我的.bashrc文件：


function bname() {
        branch="git rev-parse --abbrev-ref HEAD"
        command git push origin "$branch"
}

After doing source .bashrc, executing typing bname in the terminal results in

在执行完源文件.bashrc之后，执行在终端中键入bname会导致


fatal: invalid refspec 'git rev-parse --abbrev-ref HEAD'

How do I need to modify my bash function? Thanks.

如何修改我的bash函数？谢谢.


EDIT: To exectute the command branch, I tried sth like this:

编辑：为了执行命令分支，我尝试了如下命令：


function bname() {
        branch= command "git rev-parse --abbrev-ref HEAD"
        command git push origin $branch
}

but this results in the error

但这导致了错误


git rev-parse --abbrev-ref HEAD: command not found
[...]

更多回答

You're storing the string with the command in the variable - not running it.

您将字符串与命令一起存储在变量中--而不是运行它。

cf. the edit I made

参见我所做的编辑

Same issue - you have to run the rev-parse commandi n a subscell if you want to store the output of the command.

同样的问题-如果您想要存储命令的输出，则必须在子单元中运行rev-parse命令。

could you quickly post an answer?

你能不能快点给我回复？

Why do you need this command? git push origin HEAD does the same

为什么需要这个命令？Git推送原点磁头也是如此

优秀答案推荐

For the output of a command to be saved in a variable you need to use subshells

要将命令的输出保存在变量中，您需要使用子外壳


For example:

例如：


variable=$( ls )

would store the output written by ls to stdout in the indicated variable.

将ls写入stdout的输出存储在指定的变量中。




        branch="git rev-parse --abbrev-ref HEAD"


You should be using command substitution:

您应该使用命令替换：


branch="$(git rev-parse --abbrev-ref HEAD)"

Bash will run the command within $(...) and replace with the command's output. Incidentally, these days the $(...) format is preferred to backticks.

Bash将在$(...)内运行该命令并替换为命令的输出。顺便说一句，这些天来，$(...)格式优先于反标记。



EDIT: To exectute the command branch, I tried sth like this:
...


branch= command "git rev-parse --abbrev-ref HEAD"


You really can't guess your way through bash syntax. I highy recommend you read a tutorial or two.

你真的不能通过bash语法来猜测。我强烈建议你读一两本教程。


更多回答

its good practice to surround that with double quotes

最好用双引号将其括起来

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