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How to combine Query Parameters in nextjs 13.4(如何在nextjs 13.4中组合查询参数)

转载 作者:bug小助手 更新时间:2023-10-24 17:55:10 30 4
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const variantAction = (index: any, colorDef?: any) => {
const safeIndex = index && index > -1 ? index : 0
let colorIndex: number
if (colorDef) {
colorIndex = productDetail?.variants?.[safeIndex]?.colors.findIndex(
(color: any) => color?.name === colorDef
)
} else {
colorIndex = productDetail?.variants?.[safeIndex]?.colors.findIndex(
(color: any) => color?.name === productDetail?.variants?.[safeIndex]?.defaultColor
)
}
colorIndex = colorIndex && colorIndex > -1 ? colorIndex : 0

setCurrentVariant(safeIndex)
setImages(ImageMaker(productDetail?.variants?.[safeIndex]?.colors?.[colorIndex]))
setSelectedColor(productDetail?.variants?.[safeIndex]?.colors?.[colorIndex]?.['@id'])
setColors(productDetail?.variants?.[safeIndex]?.colors)
setColorName(productDetail?.variants?.[safeIndex]?.colors?.[colorIndex]?.name)
setSizes(productDetail?.variants?.[safeIndex]?.colors?.[colorIndex]?.sizes)
setPersonalizationTexts(null)
setError(false)
checkWishlist(safeIndex)
const s = productDetail?.variants?.[safeIndex]?.productId
const c = productDetail?.variants?.[safeIndex]?.colors?.[colorIndex]?.name

router.replace(`${pathname}?${createQueryString('c', c)}`)
router.replace(`${pathname}?${createQueryString('s', s)}`)
}

http://localhost:3000/campaign/33?xs=rw&s=gildan-18500
in above url i am able to see only router.replace(${pathname}?${createQueryString('s', s)}) but i want to combin both route.replace statements and i want to show both in url

以上URL中的http://localhost:3000/campaign/33?xs=rw&s=gildan-18500我只能看到router.replace(${pathname}?${createQueryString(‘s’,S)})但我想合并两个路径。替换语句,我想在URL中显示这两个语句


更多回答

Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking.

请澄清您的具体问题或提供更多详细信息,以突出您的确切需求。按照目前的写法,很难准确地说出你在问什么。

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